10 x n = 0.06
/10 /10
n = 0.006
.006- Just multiply both sides by the inverse of 10 (1/10) in order to get n by itself. It becomes n=6/100x 1/10 (10/100). The answer becomes 60/10,000 or .006
0.01% of 006 = 006*0.01/100 = 0.0006
Assuming x is your number, x * 10^n = x moved n decimal places. When n is positive, move the decimal point n places to the right. When n is negative, move the decimal point n places to the left. When n is 0, do nothing.
(n - 4)*10 = 10*n - 40(n - 4)*10 = 10*n - 40(n - 4)*10 = 10*n - 40(n - 4)*10 = 10*n - 40
-n(n + 10) or n(-n - 10)
.006- Just multiply both sides by the inverse of 10 (1/10) in order to get n by itself. It becomes n=6/100x 1/10 (10/100). The answer becomes 60/10,000 or .006
2 x 5 x 10 - 1= n 10 x 10 - 1=n 100 - 1 =n 99= n
0.006 = (0 x 1) + (0/10) + (0/100) + (6/1000)
6787000 = 6.787 x 10^6, so for N x 10^9 = 6.787 x 10^6, divide both sides by 10^9, and N = 6.787 x 10^-3 = 0.006787
You calculate the volume then multiply by the density of the glass. The volume is 1 x 1 x .006 = .006 cu meters Density depends on glass type but is generally about 2200 kg/cu meter Weight = .006 x 2200 = 13.2 Kg
10 x n x n = 80 x n Divide by 10 x n; n = 8 Job done.
0.00006 or 6x10-5
X Roman numeral 10
To find the number of combinations possible for a set of objects, we need to use factorials (a shorthand way of writing n x n-1 x n-2 x ... x 1 e.g. 4! = 4 x 3 x 2 x 1). If you have a set of objects and you want to know how many different ways they can be lined up, simply find n!, the factorial of n where n is the number of objects. If there is a limit to the number of objects used, then find n!/(n-a)!, where n is the number of objects and n-a is n minus the number of objects you can use. For example, we have 10 objects but can only use 4 of them; in formula this looks like 10!/(10-4)! = 10!/6!. 10! is 10 x 9 x 8 x ... x 1 and 6! is 6 x 5 x ... x 1. This means that if we were to write out the factorials in full we would see that the 6! is cancelled out by part of the 10!, leaving just 10 x 9 x 8 x 7, which equals 5040 i.e. the number of combinations possible using only 4 objects from a set of 10.
Let 5x + y + 10 = N Then 5x = N - y - 10 x = (N - y - 10) ÷ 5. Obtain the values for N and y. Substitution in the equation above will enable a value for x to be calculated.
it is 10n
log 1 = 0 if log of base 10 of a number, N, is X logN = X means 10 to the X power = N 10^x = 1 x = 0 since 10^0 = 1