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What is 10 x n 0.06 then what is n?

Updated: 9/15/2023
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13y ago

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10 x n = 0.06

/10 /10

n = 0.006

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13y ago
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10 x n equals 0.06 what is n?

.006- Just multiply both sides by the inverse of 10 (1/10) in order to get n by itself. It becomes n=6/100x 1/10 (10/100). The answer becomes 60/10,000 or .006


What is the answer in 2 x 5 x 10 - 1?

2 x 5 x 10 - 1= n 10 x 10 - 1=n 100 - 1 =n 99= n


What is 0 .006 in expanded form?

0.006 = (0 x 1) + (0/10) + (0/100) + (6/1000)


What does N equal in N times 10 to the 9th power equals 6787000?

6787000 = 6.787 x 10^6, so for N x 10^9 = 6.787 x 10^6, divide both sides by 10^9, and N = 6.787 x 10^-3 = 0.006787


How do you calculate the weight of 1m x 1m x 6mm thk glass?

You calculate the volume then multiply by the density of the glass. The volume is 1 x 1 x .006 = .006 cu meters Density depends on glass type but is generally about 2200 kg/cu meter Weight = .006 x 2200 = 13.2 Kg


Ten times the square of a non-zero number is equal to eighty times the number What is the number?

10 x n x n = 80 x n Divide by 10 x n; n = 8 Job done.


.006 x .01 equals?

0.00006 or 6x10-5


What does x r n 10 stand for?

X Roman numeral 10


How do you find all the combinations of a list?

To find the number of combinations possible for a set of objects, we need to use factorials (a shorthand way of writing n x n-1 x n-2 x ... x 1 e.g. 4! = 4 x 3 x 2 x 1). If you have a set of objects and you want to know how many different ways they can be lined up, simply find n!, the factorial of n where n is the number of objects. If there is a limit to the number of objects used, then find n!/(n-a)!, where n is the number of objects and n-a is n minus the number of objects you can use. For example, we have 10 objects but can only use 4 of them; in formula this looks like 10!/(10-4)! = 10!/6!. 10! is 10 x 9 x 8 x ... x 1 and 6! is 6 x 5 x ... x 1. This means that if we were to write out the factorials in full we would see that the 6! is cancelled out by part of the 10!, leaving just 10 x 9 x 8 x 7, which equals 5040 i.e. the number of combinations possible using only 4 objects from a set of 10.


How do you solve for x in 5x plus y plus 10?

Let 5x + y + 10 = N Then 5x = N - y - 10 x = (N - y - 10) ÷ 5. Obtain the values for N and y. Substitution in the equation above will enable a value for x to be calculated.


N x 10?

it is 10n


What is the value of log 1?

log 1 = 0 if log of base 10 of a number, N, is X logN = X means 10 to the X power = N 10^x = 1 x = 0 since 10^0 = 1