According to this rule we put electrons in the shells....here "n" show us the number of shell.
Maximum of 2n2, where n is the energy level.
The maximum is 18. This follows the law maximum = 2n2 where n = shell number, ie in this case n=3, 2n2=18.
2n2 where n is the energy level
3H2 + N2 --> 2NH3This is the Haber process which makes ammonia (NH3)
2n2 so 2 x 92 = 162 (THEORECTICALLY)
2n2 + 15n + 7 = 2n2 + n + 14n + 7 = (2n2 + n) + (14n + 7) = n(2n + 1) + 7(2n + 1) = (2n + 1)(n + 7)
2NH4NO3->2N2+O2+4H2O
Maximum of 2n2, where n is the energy level.
There are many possible answers but a relatively straightforward one is Un = 2n2 - n + 3 for n = 1, 2, 3, ...
n * 2n = 2n2
yes
M5h 2n2
(n - 4)(2n + 3)
2n2 / n = 2n
2 eyes on the road and 2 hands on the wheel
The maximum is 18. This follows the law maximum = 2n2 where n = shell number, ie in this case n=3, 2n2=18.
Well the formula for calculating the maximum amount of electrons that can be held in a shell of an atom is: 2(n)2 N being the shell number. For example: 2(1)2= 2 (the maximum amount of electrons for shell number 1)