If 3z/2 = 9 then the value of z is 6
It's rare to see an equation with two equals signs. I'm guessing something else went in between 3z and 9. 3z + 9 = 15, then z = 2 3z - 9 = 15, then z = 8 3z x 9 = 15, then z = 5/9 3z/9 = 15, then z = 45
If you mean: (3z/7) +9 = -7 then the value of z works out as -37 and 1/3
-3z - 9 = 24 ⇒ -3z -33 = 0 (subtract 24 from both sides) ⇒ -33 = 3z (add 3z to both sides) ⇒ -11 = z (divide both sides by 3) ie z = -11
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
18.
9+5=14 divided by 7 equals 2
0.2222
2
81 divided by 9 equals 9
6.2222
301.2222
9 and 3/4 divided by 2/3 equals 14.625