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41

6.403124237

x2 - 41 cannot be factorised.

9 - 4 =5, 5+36= 41

1521 - 39 squared 1600 - 40 squared 1681 - 41 squared 1764 - 42 squared

3 squared 41

X2+y2=25 (x-8)2+y2 =41

the prime factorization of 1025 is (5x5)41 or 5 squared times 41! How to do it..... 1025 5 x 205 5 x 41

1+32+52=41... The brackets go around the first part like this - (1+3)2+52=41 Because... 1+3=4 squared is 16, add that to 5 squared (25) equals 41.

5.8571

The pythagorean theorem states that in a right triangle, the hypotenuse ( the line opposite of the right angle) squared is the two sides squared and added up. In other words. a squared plus b squared equals c squared. C squared is the hypotenuse squared. then, you can find the length of C by finding the square root of C. Ex. right triangle has 2 sides with lengths. 4 and 5. the missing length is c. 4 squared plus 5 squared equals 16 plus 25 which is 41. square root of 41 is 6.4. That is the length of c. sorry if it's a little confusing.

No. it's not a prime number when x = 40, 41, 81,82 ...

your nan minus your mum squared all dived by 2 to the sum of r=20 to r= 1.

The hypothnuse is from the Pythagorean theorem: side squared + side squared = hypothenuse squared So 9^2 + 40^2 = 81 + 1600 = 1681 hypothenuse = square root 1681 = 41 feet

Presumably you mean: -2x2-3x+41 If so then the discriminant is: (-3)2-4*-2*41 = 337 The expession is: i/2+i

euler's formula is x squared + x + 41 so the numbers are 41 43 47 53 61 71 83 97

-31

Change the inches into feet and use the area formula for a circle: pi*radius squared

he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared

3x squared - x squared = 2x squared

To use the Pythagorean theorem (which is "a squared + b squared = c squared") you must take the two legs (smaller sides) in a right triangle (a and b), square each, and add them to each other (a squared + b squared). Then, you take the sum (which is c squared) and find the square root, then you are left with the hypotenuse - your answer. This works in reverse to find the legs as well. a(2) and b(2) will be either side of a right angle of a triangle. C(2) is the long diagonal slope that joins the end of a(2) and c(2) to make a triangle. for example: If a(2) is 4cm long and b(2) is 5cm long this will be the equation to solve the length of c(2) a(2) + b(2) = c(2) 4(2) + 5(2) = c(2) 16 + 25 = c(2) 41 = c(2) You get 41 by adding 16 & 25 and then you find the square root of 41 which is 6.40312 So the length of c is 6.40312 cm

1 squared = 1 2 squared = 4 3 squared = 9 4 squared = 16 5 squared = 25 6 squared = 36 7 squared = 49 8 squared = 64 9 squared = 81 10 squared = 100

100cm squared = 0.01 metres squared

9 squared is 81 and 16 squared is 256

just take a a number like 32 and square it, you have 1024 this is the smallest one. Another is 1681 since this is 41 squared