1, 3, 263, 789
No.
no
No.
yes!
It can be simplified from 6/4734 to 1/789
5 789 is divisible by 7 so there is no remainder. The answer is 827.
Nope, divisible by 3 (263 times)
2,367 is evenly divisible by 1, 3, 9, 263, 789 and 2367.
264
No. It isn't. If it doesn't have an even number in the last one of a number, it isn't
789 x 789 = 622521.
Zero out the Y to find X 3X - 2(0) = -789 3X = -789 X = -263 ------------- now to check you need to find Y, so zero out X 3(0) - 2Y = -789 - 2Y = - 789 Y = 394.5 0r 394 and 1/2 convert to fraction = 789/2 ------------ check 3(-263) - 2(789/2) = -789 -789 - 2(789/2) = -789 cancel one 2 and multiply through by that 2 -1578 + 789 = - 789 -789 = - 789 checks