.876
std::cout << std::bitset<CHAR_BIT>( 876 ) << std::endl;
The answer is 219/240.Explanation: By definition of decimal notation .876 is the same as 876/1000.We can reduce this fraction to lowest terms by dividing both the numerator and denominator by 4. Note that 4 is the Greatest Common Divisor (GCD) or Greatest Common Factor (GCF) of the numbers 876 and 1000 so that is why we divide by 4 to reduce to lowest term to get the final answer of 219/250Please click the related link for more help.
An RR interval is represented in milliseconds. Thus, to report the RR interval in seconds, simplay divide the value by 1000. e.g. RR interval of 876 divide by 1000 = 876/1000 = 0.876
7.008 = 7008/1000 = 876/125
129/1000 as a decimal is 0.129
5/1000 as a decimal = 0.005
125/1000 = 0.125 in decimal
73/1000 as a decimal is 73 ÷ 1000 = 0.073The math problem, 73 over 1000 as a decimal is 0.073.
75 over 1000 as a decimal = 0.075
It is: 17/1000 = 0.017 as a decimal
33/1000 = 0.033 as a decimal