What you have written is gibberish.
Na is sodium, a metal. Co is cobalt, a metal. These are very different metals. In this context the 3 is meaningless.
If perhaps you meant CO3 (captal O) that is carbonate: C is carbon, O is oxygen, and the 3 means three of the oxygen atoms are bound to the one carbon atom.
If you meant NaCO3 this is a nonexistent compound of the metal sodium with carbonate.
Na2CO3 is the compound sodium carbonate (washing soda), with two sodium atoms bound to one carbonate.
NaHCO3 is the compound sodium bicarbonate (baking soda), with one sodium atom and one hydrogen atom bound to one carbonate.
Sodium carbonate contains two ionic bonds, between one Na and CO3 and the other Na and CO3, because in water it brakes down to 2Na+ and CO3- ions.
Sodium: Na or the ion Na+ Carbonate: (CO3)2-
The 3 oxygen atoms in the carbonate radical ( -2 CO3 ).Sodium bicarbonate ( NaHCO3 ) is composed of three radicals:sodium ( Na+ )hydrogen ( H+ )carbonate ( -2 CO3 )
Using the periodic table of elements you can find the oxidation number of NaHCO3. Na has a charge of +1 so it's oxidation number is +1. H has a charge of +1 so again, the oxidation number is +1. CO3(carbonate) has an oxidation number of -2. As far as I know, you can find the oxidation number for CO3 because all charges together come out to be zero. With Na and H adding up to 2, CO3 can be seen to be -2. Also, CO3 is -2 because it's Lewis structure is two electrons short from being complete.
CO3 does not exist.
Sodium carbonate contains two ionic bonds, between one Na and CO3 and the other Na and CO3, because in water it brakes down to 2Na+ and CO3- ions.
It has an ionic bond between the Na and Co3 since the Na. However, the Co3 has a covalent bond, where the electrons are shared instead of being given off.
Sodium: Na or the ion Na+ Carbonate: (CO3)2-
CO3 combined with Na, K, Mg, and PO3 combined with Na, K, and NH4
The 3 oxygen atoms in the carbonate radical ( -2 CO3 ).Sodium bicarbonate ( NaHCO3 ) is composed of three radicals:sodium ( Na+ )hydrogen ( H+ )carbonate ( -2 CO3 )
Na2CO3 is a metal - polyatomic bond (Na)+1 = metal & (CO3)-2 polyatomic
since Na is a sodium + CO3 as a cabonat so it is sodium cabonate + IOH2O = sodium cabonate water haha
Yes and No. The 2 Na CO3 bonds are ionic. but the C-O bonds are covalent
sodium: Na + carbonate: CO3 2- therefore... Na2CO3 the "2" and "3" are subscripts
2 Na +and1 CO3 2-form the ionic compound,Na2CO3======
Using the periodic table of elements you can find the oxidation number of NaHCO3. Na has a charge of +1 so it's oxidation number is +1. H has a charge of +1 so again, the oxidation number is +1. CO3(carbonate) has an oxidation number of -2. As far as I know, you can find the oxidation number for CO3 because all charges together come out to be zero. With Na and H adding up to 2, CO3 can be seen to be -2. Also, CO3 is -2 because it's Lewis structure is two electrons short from being complete.
CO3 does not exist.