In electricity, P represents power, V represents voltage, and I represents current.
Electric power = Voltage * Current. (P = VI)
yes
Force (F) F = m.a and since a = dv/dt thus F = m.dv/dt Momentum (p) p = m.v and since a = dv/dt thus p = m.a.dt By switch dt from R.H.S. to L.H.S we get dp/dt = m.a thus F = dp/dt
Knowing P=VI and R=V/I we derive that P=VxV/R i.e. resistance is inversely proportional to power. Resistance for a higher power is lower.
Watts of Power are not 'drawn', it just exists, or is generated by electrical interaction in the circuit. Amperage is 'drawn' by a load. The equation you're looking for is: P = VI, so P = (10)(120) = 1200 Watts, or 1.2 kW. If you have a Three-Phase circuit, the eq changes to: P = VI(square root of 3). 1.73 is usually good enough to use as a value for the sqr 3.
150 mm Hg
(vf-vi)/ t is ?
If its from the roman numerics, it equals 6. :)
V2/r=p i2r=p vi=p
P = p + at 82 = 76 + a*20 6 = a*20 6/20 = a that is a = 3/10 or 0.3 That is the answer.
yes
p = 8
P = Pieces/PartsD = Dozen
p = 0.001
An improper expression: 2 is an exponent. P = VI V = IR P = (IR)I P = I^2R
p=1125
yes
125divided by p equals 25 = 5