315
If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.
The digit in the hundreds place in the number 2378.91 is the digit 3.
240
The digit in the hundreds place in the number 463 is the digit 4.
The digit of 0 represents the hundreds place
It is the digit of 0 that represents the hundreds place value.
415
The third digit to the left of the decimal point is the hundreds place.
If the digit in the tens place is divisible by 2 and the digit in the units place is a 0, then the number is divisible by twenty.
A zero
hundreds
The number immediately to the left of the ones place is the tens place or the 101 place. Since the value of any digit, d, there would be d*101 = d*10, it will be divisible by 10. The next number to the left is the hundreds place or the 102 place. Since the value of any digit, d, there would be d*102 = d*100, it will be divisible by 10. All the numbers further to the left have place values that are higher integer powers of 10 and so whatever the digit in that place, they will be divisible by 10. And so the answer follows.