The value of a 90mm cannon shell varies by its condition. As of 2014 these shells sell at auction for around 50.00.
Uhhh ......... Kinda depends on your exact definition of "90mm" there. Is it a 1) shell (aka: a round of ammo)? 2) complete/partial field gun (howitzer)? The question needs some clarification ......
the cannon breach is where the artillery shell is inserted for firing...................
Before the cannon is fired, the momentum is zero. So, after firing, the momentum must still be zero. The momentum of the shell is equal and opposite to that of the cannon, because there is an action and an equal reaction force. Since the momentum difference must be equal: (mv)cannon = (mv)shell Thus, (mv)c - (mv)s = 0 A simple way of looking at it is this is: If the shell is 100 times lighter than the cannon then the shell will move off 100 times faster than the cannon recoils. Remember that, in explosions, the lighter portion moves off faster than the heavier one.
90mm / 2 = 45 mm
a shell is une coquille, un coquillage (sea shell), une écaille (turtle), un obus (ammunition for a cannon)
He is worth 20 million
83
An Artillery piece (large cannon) or gun firing a large calibre shell. When the shell landed this would be an artillery explosion.
50mili
According to Forbes, it's between 34 and 39 million.
Eminem - he's world famous while Nick Cannon is not.
In portable cannon, possibly the Parrot rifled cannon. In cannon mounted in fixed positions, such as forts, possibly the Dahlgren cannons. There was also a very large bore mortar known as the Dictator that fired a 13 inch shell.