(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
x = 1 (the line intersects the x-axis at 1, and is parallel to the y-axis)We cannot write the equation on the Slope-intercept form, since the slope of the line is undefined. 1 is the x-coordinate of any point on the given line.
Point: (2, 4) Slope: -3 Equation: y = -3x+10
no it is different
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
When it is a line through the origin.
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
Point-slope form is just another way to express a linear equation. It uses two (any two points that fall on the line) and the slope of the line (Therefore the name point-slope form).y2 - y1 = m(x2 - x1)...with m as the slope.
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
Slope: -3 Point: (4, -5) Equation: y = -3x+7
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m