as we know that 1atm is equal to 760 torr therefore =622/760 =0.8184 atm.
1 ATM is equal to 760mmHg.
Thus, 622mmHg * 1atm/760mmHg = 0.818atm (approximately)
It's 2 ATM
This is equivalent to 0.2 atm. (152 mmHg)*(1 atm)/(760 mmHg)=0.2atm
646
Personally, I would go from mmHg to Atm which the conversion factor is 760mmHg/1Atm. From there, go to kPa which is 101.325KPa/1Atm. Your answer should come out to be 60.43KPa.
1.8 atmospheres =1368 mm of mercury26.4527078 pounds per square inch
Convert all the pressures into one unit and then, using Dalton's Law of Partial Pressure, you just add all the pressures together. Using these conversions(101325Pa equals 1 ATM, 1 ATM equals 760 mmHg, 1 mmHg equals 1 torr), calculate each pressure into one unit(I used mmHg) 1013000 Pa nitrogen equals 7598 mmHg of nitrogen(make sure you round using sig figs) 700 mmHg of argon equals 700 mmHg of argon 1.20 ATM of helium equals 912 mmHg of helium 790 torr oxygen equals 790 mmHg of oxygen 0.50 ATM of carbon dioxide equals 380 mmHg of Carbon Dioxide Now add all the pressures and you get: 7598+700+912+790+380= 10380 mmHg If you need to have the answer in a particular unit: 10380 mmHg = 10380 torr = 13.66 ATM = 1384000 Pa = 1,384 kPa
4.5 ATM (760 mmHg/1 ATM) = 3,420 mmHg
4.5 ATM (760 mmHg/1 ATM) = 3,420 mmHg
The answer is in the question itself:760 mmHg (= 760/760 ) = 1.00 atm , so1000 mmHg = 1000/760 = 1.32 atm
2,090
One atmosphere (ATM or torr) is equal to 760 millimeters of mercury (mmHg's)
1 standard atmosphere is 760 millimeter of mercury. 2.25 ATM is 1710 mmHg.
This is equivalent to 0.2 atm. (152 mmHg)*(1 atm)/(760 mmHg)=0.2atm
760 mm Hg = 1 atm therefore there are 1/760 atmospheres in 1 mm Hg.
760
646
395.2 mmHGSimply put.1 ATM = 760 mmHG (Torr)0.520 * 760 = 395.2 mmHG
mmHg x 0.001316 = atmospheres749 mmHg x 0.001316 = about 0.9855 atm