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Answered 2012-01-03 12:44:56

The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.

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The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5



The probability of tossing two heads in two coins is 0.25.


3/8 * * * * * That is the probability of getting EXACTLY 1H. The prob of getting one (or more) head is 7/8




Assuming that it is a fair coin, the probability is 0.9990


the probability of getting one head and one tail on three flips of a coin is 1/9


Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.


If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032


If a fair coin is tossed 5 times, the probability of getting 5 heads is:P(H,H,H,H,H) = (1/2)5 = 1/32 = 0.03125 = 3.125% ≈ 3.1%


The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.



is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? Doh!


There is a probability of 0.5 of heads on each coin, so there is a 1/2 * 1/2 *1/2 = 1/8 = 0.125 chance that all coins land heads. You can also express this as a percentage, 12.5% chance. The odds are 1 in 8 that this can happen.


The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.


The mathematical probability of getting heads is 0.5. 70 heads out of 100 tosses represents a probability of 0.7 which is 40% larger.


(1/2)^3 = 1/8th Since the initial probability (assuming independence) of getting a head in a single toss is one half (1/2) we just cube this probability because of the number of events we are performing. So if you were to try to calculate the probability of a coin being tossed 6 times it would be one half to the 6th power which is 1/64.


There is 24 or 16 outcomes. There is 4 ways to get heads once (HTTT & THTT & TTHT & TTTH). So, the probability of getting heads only once if a fair coin is tossed 4 times is 4/16 or 1/4.


The number of times a coin is tossed does not alter the probability of getting heads, which is 50% in every case, as long as the coin has not been rigged (i.e., a double-headed coin, a weighted coin) to alter the result.


The answer depends on what a winner is: 1 H?, a run of 3 H?If the winner is one H, the probability of getting exactly one winner - no more no fewer - is 5/32.



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