Sizeof is an example.
No.
There is no length function in C. You may have thought of sizeof or strlen. Perhaps.
#include<stdio.h> #include<conio.h> void main() { float f1,*Ptr1,*Ptr2; ptr1 = &fl; ptr2 = (&fl+1); printf("%u",(char *)ptr2-(char *)ptr1); getch(); }
1. identifier 2. short for function
The malloc() function is part of a class of functions that deal with the allocation of memory on the heap. int *a = malloc (sizeof (int) * 100); /* allocate 100 int's */ if (a == NULL) {...} /* deal with possible malloc failure */ /* use a, either as pointer or as array of 100 ints */ free (a); /* release memory back to the library */
If sizeof were a function, the following code would work (you can try with any other function):printf ("Function sizeof is located at %p", sizeof);On the other hand, the following code wouldn't work, as functions don't accept a type as parameter:size_t intsize= sizeof (int);
the size of an integer is determaind by using the function "sizeof(c)",here 'c' is any integer.
There are no commands in C-programming, you should use function sqrt from math.h
No.
There is no length function in C. You may have thought of sizeof or strlen. Perhaps.
It is 'sizeof'. Example: printf ("sizeof(int)=%d\n", sizeof (int));
#include<stdio.h> #include<conio.h> void main() { float f1,*Ptr1,*Ptr2; ptr1 = &fl; ptr2 = (&fl+1); printf("%u",(char *)ptr2-(char *)ptr1); getch(); }
it is sqrt in header math.h
1. identifier 2. short for function
The sizeof operator is used to determine the length of its operand (in bytes). The operand must be a type or an object of a type (a variable). The operator is a constant expression and therefore executes at compile time. As such there is no runtime overhead in repeated use of the sizeof operator.
Not possible.
C and C++ both include the built-in sizeof() operator to do just that.