The Head just before entry to the pipe becomes velocity Head at the exit of the pipe. Assuming no losses: H=u^2/2g --> u=Square root of (2gH) where H is the height of the height of the level of water in the tank above the outlet of the pipe and u is the velocity. The velocity is such that if the water left the pipe vertically upwards and assuming no losses of any sort, the water would stop at the same level as the water in the tank. The volume flow rate is then uA where A is the area of the pipe, ie (πd^2)/4 Make sure you use the same units eg, u in meters per second, d and H in meters, g=9.81 m/s^2
The velocity is constant in a steady flow pipe while in the unsteady flow the velocity is not constant.
You need to know the cross sectional area of the pipe, this would be in square feet or square meters. Then take the volume flow in cubic feet per second, or cubic meters per second, and divide it by the area, this will give the velocity in ft/sec or m/sec V=(21.22*Q)/D2 V = velocity D= diameter of pipe Q= flow
Maximum
The term "velocity", as used in physics, DOES have an associated direction. Most derived terms, such as "average velocity", also do.
Hello, Velocity in a pipe is the flow divided by the area. If the pipe is full, the area is simply pi*r². Here is a useful calulator for full pipes: http://www.tasonline.co.za/toolbox/pipe/velocity.htm
The pipe diameter doesn't matter. If the pipe is discharging a cubic foot per second then it will discharge 86400 cubic feet in a day, because that is the number of seconds in one day. One acre foot is 43560 cubic feet, so the pipe discharges 86400/43560 ~= 1.98 acre feet. On the other hand, if you meant to say the water velocity exiting the pipe is 1 foot per second (not one cubic foot per second), then, assuming you have the average water velocity, you need to figure the flow rate first. The pipe has a radius of 2 in. so its cross sectional area is pi*r^2 = pi*4 ~= 12.57. So a volume of 12.57 in.^2 * 12 in. is discharged per second, which is ~ 150.80 in.^3 or about 0.09 cubic feet. From there it's the same as above. On the other other hand, if your water velocity is not the average over the cross sectional area but instead a point velocity, say at the middle of the stream of water, then you need to figure the average velocity. You'll need a hydraulics book with pipe roughness coefficients for that.
Yes, it is actually one of the questions on a master plumbers exam
Depends on the internal diameter, and the flow velocity. Velocity of water = Delta V Internal Radius= R RxRxV= Volume
It's lacking the temperature of water to calculate its velocity having the pressure and the diameter of the pipe. The temperature of water also counts on this equation. The equation is valid for fresh water, if the density of the water is higher compared to the fresh water, the result will vary, too. It is lacking also the inner condition of the pipe. Smooth or rough. The pipe must be placed horizontally, 0º degree of inclination. The pipe must be fully straight, too.
2460 m/s
Maximum allowable water velocity is generally kept as 3m/sec. But we have seen higher velocities also work.
The Head just before entry to the pipe becomes velocity Head at the exit of the pipe. Assuming no losses: H=u^2/2g --> u=Square root of (2gH) where H is the height of the height of the level of water in the tank above the outlet of the pipe and u is the velocity. The velocity is such that if the water left the pipe vertically upwards and assuming no losses of any sort, the water would stop at the same level as the water in the tank. The volume flow rate is then uA where A is the area of the pipe, ie (πd^2)/4 Make sure you use the same units eg, u in meters per second, d and H in meters, g=9.81 m/s^2
What is the air velocity of a swallow
flow is proportional to velocity so its dependent on how fast the waters moving and the size of the pipe... check out the hazen williams nomograph
I think velocity is directly proportionate to its applying pressure.
For the instantaneous value of average velocity, average speed and average velocity are equal.