It is equal to a^3 + b^3. It can also be expressed as (a + b)*(a^2 - ab + b^2) or (a^6 - b^6)/(a^3 - b^3) or many other expressions.
No.Neither are commutative: a - b does not equal b - a, and a/b does not equal b/a.Neither is associative: (a - b) - c does not equal a - (b - c), and (a/b)/c does not equal a/(b/c).Examples of these are:4 - 2 does not equal 2 - 4.1/3 does not equal 3/1.(6 - 5) - 1 does not equal 6 - (5 - 1).(10/2)/2 does not equal 10/(2/2).
1 is the answer. -(-4)- 3 = 4-3 = 1 .
No.For example, a hexagon with equal angles and sides of lengths a,b,a,b,a,b has rotational symmetry of order 3, but it has no reflection symmetry.No.For example, a hexagon with equal angles and sides of lengths a,b,a,b,a,b has rotational symmetry of order 3, but it has no reflection symmetry.No.For example, a hexagon with equal angles and sides of lengths a,b,a,b,a,b has rotational symmetry of order 3, but it has no reflection symmetry.No.For example, a hexagon with equal angles and sides of lengths a,b,a,b,a,b has rotational symmetry of order 3, but it has no reflection symmetry.
Yes. It is like having a-b, which is a+(-b), which is -b+a, so 3-2y = 3+(-2y) = -2y+3
It equals b3.
B. 23 quarts is equal to a little more then 5 gallons
No because if a=4 and b=4 then a=b and not a can equal 6 and not b can equal 5 so ~a is not = to ~b
You can use if-else statements to check for equality.Eg:char a, b, c;scanf("%c%c%c", &a, &b, &c);if( a==b && b==c)printf("They are equal\n");elseprintf("They are not equal\n");
A = B !A = !B So Not A = Not B
3 2=B 1=A BA (Vietnamese)=3
Thing is, 3 doesn't equal 0.03... But... using false logic, it could be proved: Do we agree: 0/3 = 0/0.03 = 0 We know if: n/a = n/b then, a =b. Therefore, 3 = 0.03 However, you can't do that with a 0, so 3 doesn't equal 0.03