The square of the speed of light, which is virtually 300,000 kps so call it
90,000,000,000 kilometres per second; near enough for wiki.
1 squared
1 squared
d2
c = 17
c= sq rt of 73
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
40b squared c squared divide 5bc = 8
c = 17
A squared + B squared = C squared
a squared + b squared = c squared
a squared + b squared = c squared
c= sq rt of 73
a squared + b squared = c squared a=leg b=leg c=hypotenuse
A squared + B squared = c squared. c is across from the right angle and you subtract A from C and that's your answer
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal
A squared + B squared = C squared