first of all hexene is an unsaturated hydrocarbon made up of six carbon and twelve hydrogen atoms and so therefore its formula is C6H12. as to it being a conductor, it all depends on whether it goes into chemical reactions with elements that are conductors and whatever compound formed is said to be a conductor.
Yes: cis-3-hexene and trans-3-hexene.
3-Hexene is an alkene reactant that can either be trans or cis. Br2 is a ragent and stands for Bromine. In order to know the reaction between 3-hexene and Br2 we have to know whether it is trans-3-hexene or cis-3-hexene.
The position of double bond is different. CH3-CH=CH-CH2-CH2-CH3 is 2-hexene CH3-CH2-CH=CH-CH2-CH3 is 3-hexene
Hexene, C6H12, contains single bonds and 1 double bond
Testing, if you mean determining in your substance is hexane or hexene, could be to test the boiling point of each. Hexene's will be higher because of the double bond.
Yes: cis-3-hexene and trans-3-hexene.
3-Hexene is an alkene reactant that can either be trans or cis. Br2 is a ragent and stands for Bromine. In order to know the reaction between 3-hexene and Br2 we have to know whether it is trans-3-hexene or cis-3-hexene.
Mixture of 2-hexene and 3-hexene
I suppose that trans-3-hexene is more stable because the boiling point is greater.
The position of double bond is different. CH3-CH=CH-CH2-CH2-CH3 is 2-hexene CH3-CH2-CH=CH-CH2-CH3 is 3-hexene
Hexene, C6H12, contains single bonds and 1 double bond
Testing, if you mean determining in your substance is hexane or hexene, could be to test the boiling point of each. Hexene's will be higher because of the double bond.
it is nonpolar
Yes
There will be no reaction of Hexane as it does'nt have any reactive sites. Hexene will react only with Hcl as the double bond is nucleophilic to give poly chlorinated hexane. Hexene will not react with NaOH
It depends upon structure and position of double bond 1-hexene, 2-hexene and 3-hexene do not have the chiral center their isomer 3-methyl-1-pentene has a chiral center which is carbon no 3.
Not a polar molecule.