answersLogoWhite

0

You have to determine the Lewis structures of both before you can answer this:

Sulfur has 6 valence electrons and so does oxygen, so in SO2, we're dealing with 18 valence electrons total. First, draw single bonds between the S and each O, then fill out an octet for each O. This uses 16 electrons. The other two should be placed as a lone pair on the S. Finally, move a lone pair on one of the O's so that it forms a second bond with the S. This completes an octet for all atoms. Now count electrons groups around the S: there's a double bond, a single bond, and a lone pair.... that makes 3. So the S in SO2 is sp2 hybridized

User Avatar

Wiki User

11y ago

What else can I help you with?