You have to determine the Lewis structures of both before you can answer this:
Sulfur has 6 valence electrons and so does oxygen, so in SO2, we're dealing with 18 valence electrons total. First, draw single bonds between the S and each O, then fill out an octet for each O. This uses 16 electrons. The other two should be placed as a lone pair on the S. Finally, move a lone pair on one of the O's so that it forms a second bond with the S. This completes an octet for all atoms. Now count electrons groups around the S: there's a double bond, a single bond, and a lone pair.... that makes 3. So the S in SO2 is sp2 hybridized
Sp2,120 is the hybridization of the central atom in SO2.
With the 5 activation groups, the hybridization of the central atom in the molecules CF4 Cl2CO CH4 CS2 SO2 FCN would be sp3d.
S + o2 = so2
SO2: sulfur dioxide S + O2 --> SO2
Sulfur (S) and oxygen (O) are the two elements in sulfur dioxide (SO2).
Sp2,120 is the hybridization of the central atom in SO2.
H2=2 And S=6 So2+6=8
Co2, so2
sp2, trigonal planar, bent
With the 5 activation groups, the hybridization of the central atom in the molecules CF4 Cl2CO CH4 CS2 SO2 FCN would be sp3d.
S + o2 = so2
SO2: sulfur dioxide S + O2 --> SO2
S(s) + O2(g) SO2(g) + 296.8 kJ
Sulfur (S) and oxygen (O) are the two elements in sulfur dioxide (SO2).
The symbol equation for the reaction of sulfur with oxygen is: S + O2 → SO2
No they are not the products.Product is as this. H2SO3
1/8 S8 + O2 --> SO2 , delta H degree f = -296.9 kJ