am * an = am+n
P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
figure it out! But you can''t figure out N in this equation
seven What does n equal
m^4 n^5 - m^20 n^21
am * an = am+n
[(4/n)(9)(2/9)]^n -2x^6 - 2n=m/x^2 (8/n)^2 - 2x^6 -2n=m/x^2 (64x^2)/n^2 -2x^8 -2nx^2=m Now we know what m equals. I've got to go now. Sorry!
m = xn/(n + y)
P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P
1 Watt
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
m4n4
1 Watt = 1 N-m/sec 1800 N-m/sec = 1800 Watts
If: m = n+x/p then x = p(m-n)
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 2 words with the pattern M---N-N. That is, seven letter words with 1st letter M and 5th letter N and 7th letter N. In alphabetical order, they are: meconin melanin
For the purposes of this answer we will use the convention that x^n means xⁿ Any non-zero number to the zero power is 1 we get this from the idea that (x^n)(x^m) is x^(n+m) if n=-m, then n+m = 0 and x^ m is 1/(x^n) and (x^n)(x^m) (x^n)/(x^n)=1 so x^0 = 1 1 raised to any positive power is 1 1 raised to any negative power is 1 We can thus represent 1 as x^0 = 1 1^n = 1 1 ^(-n) = 1 (where n>0 Note that n need not be an integer since all roots of 1 are also 1)