The mode is 15 because it occurs most often
mode
In order to find the weighted mean of this set of the data, we need to know the weight for each data in the set, and this information is not given in your question.Definition: When each number ai is to have weight wi, the weighted mean is equal to(w1a1+w2a2 + ... + wnan)/(w1 + w2 + ... + wn).
The mean is 12.4
The Least Common Multiple (LCM) of 10, 12, and 14 is 420.
14. Put in order: {1, 6, 10, 12, 12, 13, 15, 19, 27, 31, 32, 40} There are 12 data items, so the median is the (12 + 1) ÷ 2 = 61/2th data item. As 61/2 is not a whole number, take the mean average of the 6th and 7th data items: 6th is 13, 7th is 15 ⇒ median = (13 + 15) ÷ 2 = 14
what is the mode of the following data 18, 17, 12, 14, 8, 21, 10, 11, 19, 20, 10, 5, 17, 12, 10, 20
14
mode
In order to find the weighted mean of this set of the data, we need to know the weight for each data in the set, and this information is not given in your question.Definition: When each number ai is to have weight wi, the weighted mean is equal to(w1a1+w2a2 + ... + wnan)/(w1 + w2 + ... + wn).
18. It is the middle number when they are listed in order.
(4*10+11+2*12+13+2*14)/10 = 11.6
10 appears more times than any other number, so it is the mode.
The mean is 12.4
11
the average of 8 10 12 14 16 is 12
The Least Common Multiple (LCM) of 10, 12, and 14 is 420.
14. Put in order: {1, 6, 10, 12, 12, 13, 15, 19, 27, 31, 32, 40} There are 12 data items, so the median is the (12 + 1) ÷ 2 = 61/2th data item. As 61/2 is not a whole number, take the mean average of the 6th and 7th data items: 6th is 13, 7th is 15 ⇒ median = (13 + 15) ÷ 2 = 14