Formula: [°C] = ([°F] − 32) × 5⁄9
42 degrees Fahrenheit = 56 degrees Celsius.
-60 degrees celsius = -76 degrees Fahrenheit [°F] = [°C] × 9⁄5 + 32 [°C] = ([°F] − 32) × 5⁄9
The freezing point of propane is approximately -188.2 degrees Celsius.
(-34) degrees Fahrenheit = -36.7 degrees Celsius.[°C] = ([°F] − 32) × 5⁄9
-15ºC = 5.0ºFUse this formula to convert degrees Celsius (C) to degrees Fahrenheit (F): (C x 1.8) + 32 = F
5°F = -15°C (5°F - 32) multiplied by 5/9 = -15°C
It was minus 42 degrees F.
42 degrees Celsius = 107.6 degrees Fahrenheit
-14.8 F
42 degrees Fahrenheit = 5.56 degrees Celsius
-60 degrees celsius = -76 degrees Fahrenheit [°F] = [°C] × 9⁄5 + 32 [°C] = ([°F] − 32) × 5⁄9
(-50) degrees Celsius = -58 degrees Fahrenheit.
The freezing point of propane is approximately -188.2 degrees Celsius.
-23.2F
-26.1111111 Celsius
That is because F = 9/5 C + 32 for F and C to be the same, F = C, solve: F = C = 9/5 C +32 C -9/5 C = 32 -4/5C = 32 C = -5/4 (32) = -40 F = C = -40
21.2 degrees Fahrenheit
(-34) degrees Fahrenheit = -36.7 degrees Celsius.[°C] = ([°F] − 32) × 5⁄9