The reaction will be Tin Nitrate and Hydrogen Gas.
When tin is placed in nitric acid (HNO3), a chemical reaction occurs in which tin is oxidized by nitric acid to form tin(II) nitrate (Sn(NO3)2) and nitrogen dioxide gas (NO2) is evolved. This reaction can be represented by the equation: 3Sn + 8HNO3 -> 3Sn(NO3)2 + 4H2O + 2NO2
I think you have mixed your English grammar. The question should read 'Hydrochloric Acid plus Tin'.
Nitiric acid
ZnCO3 + 2HNO3 ----> Zn(NO3)2 + H2O + CO2
Just gold and nitric acid. Gold's impervious to nitric acid.
When tin is placed in nitric acid (HNO3), a chemical reaction occurs in which tin is oxidized by nitric acid to form tin(II) nitrate (Sn(NO3)2) and nitrogen dioxide gas (NO2) is evolved. This reaction can be represented by the equation: 3Sn + 8HNO3 -> 3Sn(NO3)2 + 4H2O + 2NO2
I think you have mixed your English grammar. The question should read 'Hydrochloric Acid plus Tin'.
I guess it is called as NH4OH
Nitiric acid
ZnCO3 + 2HNO3 ----> Zn(NO3)2 + H2O + CO2
Just gold and nitric acid. Gold's impervious to nitric acid.
= Copper(II) chloride + Nitric acid
Nitric acid plus zinc oxideNitricoxide
The balanced chemical equation for the reaction between nitric acid and sodium hydroxide is: HNO3 + NaOH -> NaNO3 + H2O. Therefore, the coefficient for nitric acid is 1, for sodium hydroxide is 1, for sodium nitrate is 1, and for water is 1.
The balanced equation for the reaction between tin, nitric acid, ammonium hydroxide, and citric acid is complex and involves multiple steps. The reaction may form tin citrate, ammonium nitrate, and water as the products. It is recommended to consult a detailed chemical reference or use a chemical equation balancer for accurate results.
Sulfuric acid plus copper (II) nitrate yields nitric acid plus copper (II) sulfate. Sulfuric acid plus copper (I) nitrate yields nitrous acid plus copper (I) sulfate.
No, it does not