0
s
GUNDLURI MOHAN
Wiki User
∙ 10y ago64Kbps
Add your answer:
Earn +20 pts
What is the bandwidth of N bit binary coded PCM?
It is same as the bit rate. B = R = nfs where n= no of bits fs= sampling frequency R= bit rate
When analog voice signal converts into digital signal the bandwidth needs 64kbps. Why?
PCM technique is used to convert analog voice signals into digital. In PCM the analog frequency is first sampled and then converted into binary bits. Each samples are taken as 8bits long. Basic communication theory requires that a minimum sampling rate of twice the frequency of the signal to be sampled will result in an accurate representation of the original signal.Human voice can have max 4000hz frequency, therefore sampling rate should be 8000 samples/sec.Which implies required bit rate for transmitting voice is 8000*8 = 64000 bits/sec = 64kbps.
What are the 5 voice qualities?
PCM technique
How many bits are in a conventional PCM voice sample?
8
What you will become if you take pcm with c plus plus?
A bit of sound, depending how much PCM you take.
What sampling rate from a sound card would you require if you want to be able to record CD sound quality?
The standard CD is two-channel 16-bit PCM encoding at a 44.1 kHz sampling rate per channel.
A 2MB PCM has how many voice channels?
There are 32 channels in total. Out of which 31 are voice channels and 1 is signalling channel
What is the sampling rate for PCM if the Frequency ranges from 1000 to 4000 Hz?
>8000hz
How do you convert WAV mono files to 8K 16 Bit pcm format?
Thank you Sir.
Difference between e1 and t1 in telecommunication?
Differing Characteristics :-In E1 Encoding/Decoding is followed by A-Lawwhile in T1 Encoding/Decoding is followed by µ-Law.In E1 - 13 Number of Segments in Characteristicswhile in T1 - 15 Number of Segments in Characteristics.In E1 - 32 Number of Timeslots / PCM Framewhile in T1 - 24Number of Timeslots / PCM Frame.In E1 - 8 x 32 = 256 number of bits / PCM Frame while in T1 - 8 x 24 + 1* = 193 number of bits / PCM Frame. (* Signifies an additional bit).In E1 - (125µs x 8)/256 = approx 3.9µs is the length of an 8-bit Timeslot while in T1 - (125µs x 8)/193 = approx 5.2µs is the length of an 8-bit Timeslot.In E1 - 8000/s x 256 bits = 2048kbit/s is the Bit Rate of Time-Division Multiplexed Signal while in T1 - 8000/s x 193 bits = 1544kbit/s is the Bit Rate of Time-Division Multiplexed Signal.
If only four computers are transmitting digital data over a T-1 line what is the maximum possible data rate for each computer?
Multiplexes 4 channels Each frame has 8 bits per channel plus one framing bit Frame size= 4*8 + 1 = 33 bits per frame For voice each channel contains one word of digitized data (PCM, 8000 samples per sec) Data rate 8000x33 = 0.264 Mbps
How ISDN PRI equals 2.048 mbps?
As we know that voice signal is of frequency 3.3 Khz,and as per the Nyquist Rate or PCM quantization rate for transmission we required signal of >=2f(here 'f' is GIF [3.3]=4).and each sample of data is a byte. DS0: provides one 64kbps channel.E1: 32 DS0 or 32 channels with 64kbps Also we know that voice signal frame consisits of 32 bytes .Hence value of an E1 will be =2x4Khzx8bitsx32slots =2.048Mbps
