First let's talk about units of pressure so that we can understand my answer later.
The unit for pressure is the pascal (Pa), equal to one newton per square meter (N/m2 or kg/m·s2)
A simple way to think about pressure is in this case is to realize that water has weight to it. Gravity is pulling the water towards the center of the earth, and the deeper you go the more water is above you and the greater the pull. Under gravitational constraints like this the pressure of any fluid can be calculated as the gravitational constant (g) multiplied times the density (ρ) multiplied times the height (h). In the case of water the calculation is relativly stright forward because it can be considered an incompressable fluid and therefore the density remains constant.
So to answer your question, the density of water is approxamtley 1000kg/m3 the height is 100 feet or 30.48 meeters ( to keep units consistant) and the gravitational constant on earth is approximatly 9.81 m/s2 slksj.
So we have to calculate it we take ρ*g*h which for this case is (1000kg/m3)*(9.81 m/s2)*(30.48m) which gives us 299008.8 kg/m·s2 or 299.0088 kPA.
We also have to take into account the pressure from gravity pulling on the air, this is not a straight forward calculation because air does not have a constant density (ρ) and must be integrated over. Luckly we know airpressure at sea level is 1atm=14.7psi = 101.325 kPa
So 299.0088 kPa + 101.325kPa = 400.334kPa
The short answer is 400.334 kPa, or about 3.951 atm, or 58.080 psi depending on what unit system you prefer.
Pressure = 10 * depth * density Density of water = 1000 kg/m3 depth = 3 feet = 0.9 meters Hence Pressure = 10 * 0.9 * 1000 Pressure due to water = 9 * 103Pa
About 37 pounds per square inch.
1470 psi
100 Celsius
The Celsius scale is in fact based on water, it freezes at 0 degrees and boils at 100 degrees Celsius at 760 mm Hg pressure.
The boiling point of pure water is typically about 100 degrees Celsius. This value can vary based on factors such as pressure. Additionally, impurities in a sample of water can alter its boiling point.
It means that:* There is water, and * It is under higher pressure than normal, i.e., more than 1 atmosphere (or bar) of pressure. At higher pressures, water can achieve a higher temperature (i.e., higher than 100 degrees Celsius) before it boils.
Water boils at 100C at 1 ATM
Yes they have ben spoted that deep under water.
100 Celsius
Yes, it can. Under normal temperature and pressure, pure water does.
Fresh water under atmospheric pressure boils at 100 C or at 212 F
The same reason pressure builds up when you pile a thousand pounds of dirt onto someone. If you are 100 feet under water you are under many tons of water. Good thing all of that weight isn't directly exerted onto you, but spread out evenly in the ocean.
put it under pressure
100 feet by 100 feet by one inch equates to 6,233.76 gallons of water.
Assuming that 100 dregess is your way of saying 100 degrees Celsius, it is the boiling point of pure water, under normal atmospheric pressure.
Water boiling temperature depends on pressure: at standard P it is 100 oC. High up in the mountains where air pressure is lower b.p.= eg. 98 oC (< 100)
When water is placed under pressure it lowers its boiling point. Therefore, if you put it under pressure you can heat it to temperatures much higher than 100 C. However, if you lose that pressure, say by breaking the tank holding the pressurize water, the water will quickly boil off and can cause explosions due to the rapid expansion of the vapor.
100°C (the definition of 100 degrees Celsius is the triple point of water) By "normal" I assume you mean standard pressure.
fresh water under atmospheric pressure