What is smallest number using 3 digits?
depends, you want it before or after the decimal point? before= 001 after= .001
In order to make the smallest possible number with a set of digits, you want the least valued number in the greatest valued place. For 5 digits, you would want the least digit, 0, in the ten thousands place. You would then want the second least digit, 3, in the thousands place, and so on. For the digits 0,3,5,7,9 the smallest possible number would therefore be 03,579 or 3,579.
What would be the remainder left if the greatest prime number of 3 digits is divided by the smallest prime number?
What is the smallest possible 4-digits number that can be formed that is divisible by 2 by 3 and by 5?
What is the smallest 7-digit odd number in which the ones digit is the sum of the thousands and ten thousands digits?
To make the smallest digit you can, you want to use the smallest numbers you can. Since we need to use 4 different digits, we'll use:0, 1, 2, 3 Now to generate the smallest number, you'll want the lowest digits to be the left most numbers. The exception here is, you don't want to begin a number with 0, so 1 is the next best choice. A four digit example: 1023 <-- because 0123 doesn't…
Start with the smallest multiple of 13 and continue with the next smallest until finding one that fits the specifications. 13, sum of digits is 1 + 3 = 4 which is not prime 26, sum of digits is 2 + 6 = 8 which is not prime 39, sum of digits is 3 + 9 = 12 which is not prime 52, sum of digits is 5 + 2 = 7 which is prime…
In a proper fraction the numerator is smaller than the denominator. Since every two-digit number is larger than every one-digit number, there must be a one-digit numerator and two-digit denominator comprising 3 digits total. The greatest fraction will be the one with the largest possible numerator and smallest possible denominator. Choose a numerator of 9 (the largest one-digit number) and a denominator of 10 (the smallest 2-digit number). All 3 digits are different. The answer…
Since the sum of the digits is divisible by 3, the original number is also divisible by 3. Since the sum of the digits is divisible by 3, the original number is also divisible by 3. Since the sum of the digits is divisible by 3, the original number is also divisible by 3. Since the sum of the digits is divisible by 3, the original number is also divisible by 3.