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Formula: K3[Au(CN)6]

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14y ago

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Related Questions

Are copper gold aluminum lithium have multiple valences?

Lithium is only monovalent. Aluminium is trivalent; rarely is bivalent or divalent. Gold is monovalent or trivalent.


What do you call a material of or containing gold in the trivalent state?

auric


What is the formula for the compound that forms from potassium and cyanide?

To answer this you need a roman numeral on gold to know the charge on it. Assuming it would be (I)... the formula would be KAu(CN)2


Of or containing gold in the trivalent state AURIC?

Au(III) ions are considered to be in the trivalent state of gold, also known as auric state. This state typically involves gold atoms that have lost three electrons. Compounds containing gold in this state may exhibit distinctive chemical properties compared to other oxidation states of gold.


What is the formula for gold I iodide?

Formula: AuI


What is the formula to the element gold?

The chemical formula for the element gold is Au.


What is the Formula for gold ( I ) oxide?

The chemical formula is Au2O.


What is the formula of gold?

The chemical symbol of gold is Au.


What is the chemical formula for gold oxide?

Formula: Au2O3


What metals is the most stable gold zinc silver potassium?

Gold is the most stable out of the listed metals. Silver is also relatively stable, while zinc and potassium are more reactive.


What is the formula for gold phosphide?

Gold III phosphide is AuP.


What is the mass of potassium if a potassium sample contains 5 times the number of atoms as in 9.85 grams of gold?

The gram atomic mass of gold is 196.967 and that of potassium is 39.0983. Therefore, equal numbers of atoms of potassium are supplied by 39.0983/196.967 the mass of potassium compared with gold. 5 X 9.85 = 49.25. This contains the same number of gold atoms as 49.25(39.0983/196.967) or 9.78 grams of potassium contains of potassium atoms, to the justified number of significant digits (limited by the number "9.85", assuming that "5" is intended to be exact.)