A 16-bit number is a number made of 16 binary digits. The largest 16-bit number is 1111111111111111 in binary (sixteen 1s), which is equal to 65535 in decimal.
This is presuming that you are using an 'unsigned' 16-bit number, which can store numbers from 0 to +65535. If you want to be able to store negative numbers as well, 16-bits will let you store numbers from -32768 to +32767, if you use the two's-complement method for storing a 'signed' value.
The largest number in 16-bit binary is 65535 and is represented by 11111111-11111111.
216-1 or (2^16)-1
Unsigned: 216-1. Signed: 215-1.
The number of data lines required in a 16-bit microprocessor is 16, in the internal view, but could be something else, such as 8, in the external view. In the 8086/8088, the processor is 16 bits, and its internal data bus is 16 bits. The 8086 provides 16 bits on the external bus, but the 8088 provides 8 bits, even though they are the same internal processor - the 8088 simply uses two memory cycles to move one word. The largest number that can be represented on a 16 bit bus depends on the interpretation of that number. An unsigned 16 bit number ranges from 0 to 65535, so 65535 is the largest value when unsigned. A 16 bit two's complement signed number ranges from -32768 to +32767, so +32767 is the largest value when signed.
That would be 216 - 1, or 65535.
In a 16 bit number there must be from zero to 16 '1'. If a bit does not have value zero then it has a value of 1. Nothing else can be represented by a bit. Example 0000 is a 4 bit number. Each bit is a zero. 1010 is also a four bit number. 0000111100001111 is a 16 bit number. 1100110011000001 is also a 16 bit number.
For an unsigned integer, that would be 216-1. For a signed integer in 2's complement notation, the largest number would be 215-1.
The largest number which can be stored in an 8 bit memory byte is 255 . The largest prime number below 255 is 251.
The largest number which can be stored in an 8 bit memory byte is 255. The largest prime number below 255 is 251.
The largest number which can be stored in an 8 bit memory byte is 255 .The largest prime number below 255 is 251.
Largest 8 bit unsigned number is 11111111 binary thus making 255 in decimal.
largest prime no. 6-bit is 61.
In unsigned notation, 0xFFFF (65,535 decimal) is the largest value that will fit in a 16-bit register. In signed notation, 0x7FFF (32,767 decimal) is the largest because the most-significant bit denotes the sign.
The largest unsigned 8-bit number is 255.
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
(2 to the power of 16 ) - 1 = 65535
this means 26-1=63 .63 is the largest number can be stored in 6 bit pattern so nowlargest prime number in between 63 is 61
The answer depends on the number of binary digits (BITS) in the word. The largest 8-BIT hexadecimal word will be 16^8 -1 = 4,294,967,295.Nowadays, 32 and 64 bit words are common: a 64 bit word could hold a number greater than 1.1*10^77 while a 128 bit word (not yet in common use) would exceed 1.3*10^154 or a Googol^1.5
The largest number which can be stored in 8 bits is 255. The largest prime number which is less than or equal to 255 is 251.
A signed 16 bit number can represent the decimal numbers -32768 to 32767.
16*625 = 10000 so the largest 4-digit multiple must be 16*624 = 9984