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What is the oxidation number of Cr2O3?
+3 for Cr and -2 for O
What is the oxidation number of Cr in CrBr?
In CrBr (chromium monobromide) Cr would have an oxidation number of +1. This compound is not known perhaps you meant CrBr3, where chromium has an oxidation number of +3
What is the change in the oxidation number of Cr?
The change in oxidation number of Cr depends on the specific reaction or compound involved. For example, in the reaction from Cr(III) to Cr(VI), the oxidation number of Cr changes from +3 to +6, indicating an increase in oxidation state.
What is the oxidation number for CrPO4?
The oxidation number for Cr in CrPO4 is +3. This is because the overall charge of the compound is neutral, and the oxidation numbers for oxygen (-2) and phosphorus (+5) are known. By calculation, we determine the oxidation number of Cr to be +3.
What is the oxidation number for Cr in Cr2O3?
+6 for Cr, -2 for each O in Cr2O72-oxidation number for oxygen is -2 so 7 of them makes -14 in total but the compound has an overall charge of 2- so therefore +12 is required. As there are two chromium then the oxidation number for each one is +6
What is the oxidation number of Cr2O3?
+3 for Cr and -2 for O
What is the oxidation number of Cr in CrBr?
In CrBr (chromium monobromide) Cr would have an oxidation number of +1. This compound is not known perhaps you meant CrBr3, where chromium has an oxidation number of +3
What is the change in the oxidation number of Cr?
The change in oxidation number of Cr depends on the specific reaction or compound involved. For example, in the reaction from Cr(III) to Cr(VI), the oxidation number of Cr changes from +3 to +6, indicating an increase in oxidation state.
What is the oxidation number for CrPO4?
The oxidation number for Cr in CrPO4 is +3. This is because the overall charge of the compound is neutral, and the oxidation numbers for oxygen (-2) and phosphorus (+5) are known. By calculation, we determine the oxidation number of Cr to be +3.
What is the oxidation number for Cr in Cr2O3?
+6 for Cr, -2 for each O in Cr2O72-oxidation number for oxygen is -2 so 7 of them makes -14 in total but the compound has an overall charge of 2- so therefore +12 is required. As there are two chromium then the oxidation number for each one is +6
What is the oxidation number of element Cr?
As with any other element, the oxidation number of Cr depends on whether and how it is chemically bonded. The oxidation number of pure elements is arbitrarily defined to be 0. In compounds, Cr has oxidation numbers of +2, +3, and +6, depending on the compound.
What is the oxidation number of Al2Cr6O21?
The oxidation number of aluminum (Al) is +3, the oxidation number of chromium (Cr) is +3, and the oxidation number of oxygen (O) is -2. Therefore, in Al2Cr6O21, the total oxidation number would be +6 from aluminum, +18 from chromium, and -42 from oxygen, resulting in a net oxidation number of -18 for the compound.
What is the oxidation number for NH42CrO4?
The oxidation number of a compound is zero (nitrogen -3, hydrogen +1, chromium +3, oxygen -2).
What are the oxidation numbers in chromiumIII oxide?
In chromium(III) oxide, the oxidation number of chromium is +3 and the oxidation number of oxygen is -2. This compound has the chemical formula Cr2O3.
What is the oxidation number for k2cro4?
In K₂CrO₄, the oxidation number of potassium (K) is +1, and the oxidation number of oxygen (O) is -2. Since the compound is neutral, the oxidation number of chromium (Cr) can be calculated as follows: 2(+1) + Cr + 4(-2) = 0. Solving for chromium, the oxidation number of chromium in K₂CrO₄ is +6.
What are the oxidation numbers of kmno4 plus kno2 plus h2so4 equals mnso4 plus H2O plus kno3 plus k2so4 oxidation numbers?
In KMnO4, Mn has an oxidation number of +7, KNO2 has N with an oxidation number of +3, and H2SO4 has S with an oxidation number of +6. In MnSO4, Mn has an oxidation number of +2, H2O has O with an oxidation number of -2, KNO3 has N with an oxidation number of +5, and K2SO4 has S with an oxidation number of +6.
What is the the oxidation number of chromium in Cr2(SO4)3?
Well, without being given an equation, we presume you mean the o.n. of chromium. H in this is +1, so H+H=+2 4 x O= -2 x 4 = -8, therefore Cr = +6 as the whole element has to equal zero. and i do believe in this form it normally goes to Cr +3
