It is 2500.
The integers are -1, 1 and 3.
-1, 1, 3, 5
101
It is 100*(100+1)/2 = 50500.
Should be 50! Every odd integer is 1 less than the corresponding even integer and there are 50 of each in 100...
The first odd positive integers are "1" and "3" which the sum is 4.
4900
The sum of the integers from 1 to 100 inclusive is 5,050.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
The integers are -1, 1 and 3.
-1, 1, 3, 5
101
The formula for the sum of the squares of odd integers from 1 to n is n(n + 1)(n + 2) ÷ 6. EXAMPLE : Sum of odd integer squares from 1 to 15 = 15 x 16 x 17 ÷ 6 = 680
The numbers are -3, -1, and 1.
The sum of all the odd numbers from 1 through 100 is 10,000
Let's talk this out and see if we can work it out. The sum of the first N odd integers means, 1+3+5+7+9+11+... Where N is how many odd numbers we're adding. Let's choose numbers for N, and see if we can find a pattern. N=1 --> 1 (sum of the first odd integer) N=2 --> 1 + 3 = 4 (sum of the first 2 odd integers) N=3 --> 1 + 3 + 5 = 9 (sum of the first 3 odd integers) N=4 --> 1 + 3 + 5 + 7 = 16 Do you notice a pattern yet? Take a look at when N = 2, what is the sum? That's right, 4! and when N = 3... the sum is 9. N = 4 the sum is 16.... I see a pattern, do you? Answer: If you don't, you'll notice that the sum of the first N odd integers is always = N2
The average of the two odd integers is 28. Therefore the two integers are 28-1 and 28+1, i.e 27 and 29.