It will help us to In SOP standard form, every variable in the domain must appear in each term. This form is useful for constructing truth tables or for implementing logic in PLDs.
need help to simplify boolean expression
demorganization is used to reduce the Boolean expressions
FALSE.... cuz in && operator the compiler chk both of the expression if any of the expression is false then answer will be false.. for true result both of d expression must be true... by warrior2pnk
a ⊕ b = ab' + a'b
(a'b+b'a)'
Through Boolean algebra simplification, a Boolean expression is translated to another form with less number of terms and operations. A logic circuit for the simplified Boolean expression performs the identical function with fewer logic components as compared to its original form.
In a boolean algebraic expression if the ^ is replaced by v and v replaced by ^ then that becomes dual of that boolean expression.
Simplification of Boolean expressions reduces the number of operations or the circuitry required for implementation. However, it is important to note that simplification is not necessarily a good thing. This is particularly the case in hardware design, and is easy to understand when using KV diagrams for simplification: in cases where simplification yields a KV diagram with more than one non-overlapping zones (areas where the boolean expression equates to the desired state), transitioning between those non-overlapping zones can cause gliches; high frequency transitions of the output signal through its inverse. This can be caused by different speed of signals through the circuitry, for example when different paths use different gates or numbers of gates. In these cases, it is generally useful to expand the expression such that the disjoint areas in the fully simplified KV diagram have a link through which they can overlap.
Construct circuit for Boolean expression (Mention out put at each step) (PÚ~ Q) Ù (P Ú Q)
xy+xy'
need help to simplify boolean expression
demorganization is used to reduce the Boolean expressions
Boolean expression
That is correct. Any processor worth it's salt will, when evaluating an expression like "1 and 0 and 1 and 1 and 0" will get as far as the first zero and "realize" that full expression will result in false regardless of the rest.
FALSE.... cuz in && operator the compiler chk both of the expression if any of the expression is false then answer will be false.. for true result both of d expression must be true... by warrior2pnk
a ⊕ b = ab' + a'b
A boolean expression.