Light will be reflected at an angle of 30deg from the normal. We can work out the angle of refraction using the formula: n(1) sin(incident angle) = n(2) sin(refracted angle) We will assume the refractive index given is the relative refractive index n(2)/n(1). So sin(30)/1.5 = sin(r) r = 19.5 deg As the reflectedd and refracted rys are on the same side of the normal we can subtract them from 180 to get the angle between them: 180 - 19.5 - 30 = 130.5
Incident light hits a prism, refracted or reflected light emerges from it. In what manner it is different from the incident light depends on the angle of incidence and the angles of the prism. Commonly it may be refracted, dispersed or reflected back.
The relation between the incident ray and reflected ray is described by the material which is reflecting the incident ray. depending upon the material used the incident ray is scattered or reflected or refracted or transmitted or absorbed. For example if you take rainbow the sun light is incident on the rain drop , it reflected back of drop several times and due to that we get the rainbow with various colours.
Rephrase the question PLEASE. I can't even prove there is a question in that sentence.
The angle of incidence equals the angle of reflection.
When light travels through a transparent medium it is slowed down according to the refractive index of the medium. Also if light is incident at an angle onto a surface of such a material, the light rays are bent or refracted by an angle at the boundary of the material, the angle again depending on the refractive index.
It only happens when the incident ray is shone at 90 degrees. The refracted ray will then travel along the same path as the incident ray. This is known as total internal refraction.
If a beam of light enters a substance with a higher density than air and at an angle, the light is refracted so that an object on the far side of the substance appears to be closer to the observer. If the density of the substance is lower than that of air, the light is refracted away from the observer and the object being viewed appears to be farther away.
yes .. at any interface when light passes from one medium to another part of it gets reflected and remaining refracted. so some amount of light incident when passing from air to glass gets reflected. but in the reverse way i.e, from glass to air there is chance for all the light incident to get reflected as in the case of total internal reflection. and again coming to your case the amount of light reflected follows the laws of reflection i.e, angle of incidence is equal to the angle of reflection. the light which got refracted follows the snell's laws of refraction.
Either when they are both 0 degrees (the incident ray is perpendicular to the surface) or the refractive indices of the two media are the same.Either when they are both 0 degrees (the incident ray is perpendicular to the surface) or the refractive indices of the two media are the same.Either when they are both 0 degrees (the incident ray is perpendicular to the surface) or the refractive indices of the two media are the same.Either when they are both 0 degrees (the incident ray is perpendicular to the surface) or the refractive indices of the two media are the same.
The refractive number of a substance is a measure of how much the speed of a wave changes compared to the speed in a reference medium i.e. air or a vacuum. The critical angle is the angle of incidence above which total internal reflection occurs. When the angle of incidence of the light ray leaving the glass is less than the critical angle, the light ray speeds up on leaving the glass and is refracted away from the normal.
A ray of light which strikes the surface is called incident ray and a surface which is reflected is called a reflected ray
The angle of incident is 45 degrees. The incident and reflected ray have the same magnitude and if the sum of the magnitudes is 90 degrees the incident is 45 degrees.