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Light will be reflected at an angle of 30deg from the normal. We can work out the angle of refraction using the formula: n(1) sin(incident angle) = n(2) sin(refracted angle) We will assume the refractive index given is the relative refractive index n(2)/n(1). So sin(30)/1.5 = sin(r) r = 19.5 deg As the reflectedd and refracted rys are on the same side of the normal we can subtract them from 180 to get the angle between them: 180 - 19.5 - 30 = 130.5

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Q: What is the angle between a reflected and a refracted rays when a light ray is incident at 30 degrees on a parallel block of thickness 5cm and refractive index 1.5?
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