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Light will be reflected at an angle of 30deg from the normal. We can work out the angle of refraction using the formula: n(1) sin(incident angle) = n(2) sin(refracted angle) We will assume the refractive index given is the relative refractive index n(2)/n(1). So sin(30)/1.5 = sin(r) r = 19.5 deg As the reflectedd and refracted rys are on the same side of the normal we can subtract them from 180 to get the angle between them: 180 - 19.5 - 30 = 130.5
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What relationship exist between the intensity of the incident reflected and refraacted rays?
The intensity of the incident ray is equal to the sum of the intensity of the reflected ray and the refracted ray, according to the law of conservation of energy. This means that some of the incident light is reflected and some is refracted when transitioning from one medium to another. The specific ratios of reflection and refraction depend on the properties of the materials involved.
Why is light internally reflected in a raindrop?
Light is internally reflected in a raindrop because of the difference in the refractive index between air and water. When light enters the water droplet at a certain angle, it bends due to the change in medium. If the angle is just right, the light is reflected internally off the surface of the droplet and then refracted again when it exits, creating a rainbow.
How does incident light emerge from a prism?
Incident light hits a prism, refracted or reflected light emerges from it. In what manner it is different from the incident light depends on the angle of incidence and the angles of the prism. Commonly it may be refracted, dispersed or reflected back.
When light is incident on a surface at 30 degrees it is found that reflected ray and refracted ray are perpendicular to each other Find angle of refraction How?
When light is incident on a surface at 30 degrees and the reflected and refracted rays are perpendicular, it means the angles of reflection and refraction add up to 90 degrees (since they are complementary angles). Therefore, the angle of refraction can be calculated as 60 degrees by subtracting the incident angle from 90 degrees. This is based on the principle of Snell's Law, which states that the angle of incidence and angle of refraction are related through the refractive indices of the two mediums.
Prove that the angle between reflected and refracted rays is 90 degree if a ray incident from denser to rarer medium?
When a ray of light travels from a denser medium to a rarer medium, the angle of refraction is greater than the angle of incidence. The reflected ray and the refracted ray lie in the same plane as the incident ray. Using Snell's Law and the principle of reflection, we can show that the sum of the angles formed by the refracted and reflected rays with the normal is equal to 90 degrees.
How is an incident ray related to a reflected ray?
The relation between the incident ray and reflected ray is described by the material which is reflecting the incident ray. depending upon the material used the incident ray is scattered or reflected or refracted or transmitted or absorbed. For example if you take rainbow the sun light is incident on the rain drop , it reflected back of drop several times and due to that we get the rainbow with various colours.
When the refracted light is bent back into the incident material is called a?
When the refracted light is bent back into the incident material, it is called total internal reflection. This occurs when the angle of incidence is greater than the critical angle, causing all the light to be reflected back into the original medium rather than refracted. Total internal reflection is the principle behind optical fibers and mirages.
Why is there a loss of intensity when light is reflected?
When light is reflected, some of it is absorbed by the reflecting surface and some is scattered in various directions, leading to a loss of intensity in the reflected light compared to the incident light. Additionally, light can also be refracted or transmitted through the surface, further reducing the overall intensity of the reflected light.
When light passes from air to glass the light may change direction due to reflection?
yes .. at any interface when light passes from one medium to another part of it gets reflected and remaining refracted. so some amount of light incident when passing from air to glass gets reflected. but in the reverse way i.e, from glass to air there is chance for all the light incident to get reflected as in the case of total internal reflection. and again coming to your case the amount of light reflected follows the laws of reflection i.e, angle of incidence is equal to the angle of reflection. the light which got refracted follows the snell's laws of refraction.
What happen when light travel through medium?
When light travels through a transparent medium it is slowed down according to the refractive index of the medium. Also if light is incident at an angle onto a surface of such a material, the light rays are bent or refracted by an angle at the boundary of the material, the angle again depending on the refractive index.
What happens when a ray of light strikes a flat water surface?
Whenever light hits a water surface, some of the light is reflected off, and some of it is refracted, or "bent", deeper into the water. The proportion that is reflected and refracted depends on the wavelength of the light and the angle of incidence. When light goes straight down into the water, most of it penetrates the surface and goes into the water. When the light impacts at an angle, more of the light is reflected away.
How is the critical angle related to the refractive index of a medium?
The refractive number of a substance is a measure of how much the speed of a wave changes compared to the speed in a reference medium i.e. air or a vacuum. The critical angle is the angle of incidence above which total internal reflection occurs. When the angle of incidence of the light ray leaving the glass is less than the critical angle, the light ray speeds up on leaving the glass and is refracted away from the normal.
