###### Asked in Math and ArithmeticGeometry

Math and Arithmetic

Geometry

# What is the answer for a square pyramid with a base edge length of 15 and a slant height of 36?

## Answer

###### Wiki User

###### August 07, 2013 5:45AM

It depends on what the question is: the volume, surface area, colour, smell? Some of these can be answered with the given information , others can't. But since you have not bothered to provide that crucial bit of information about wat is required, I cannot provide a more useful answer.

## Related Questions

###### Asked in Math and Arithmetic, Geometry

### How do you find the slant height of a pyramid with a rectangular base?

If you make a line from the top of the pyramid to the center of
the base, you have the height of the pyramid. This meets at the
midsegment of a line going across the base. Since the height of a
pyramid is perpendicular with the base, get this:
the height, a line of 1/2 the length of the base, and the slant
height form a right triangle. So, you can use the Pythagorean
Theorem! For example, if the base length is 6 and the height of the
pyramid is 4, then you can plug them into the Pythagorean Theorem
(a squared + b squared = c squared, a and b being the legs of a
right triangle and c being the hypotenuse). 1/2 the length of the
base would be 6 divided by 2=3. 3 squared + 4 squared = slant
height squared. 9+16=slant height squared. 25= slant height
squared. Slant height=5 units. You're welcome!

###### Asked in Math and Arithmetic, Algebra, Geometry

### When you see a picture of a right pyramid with a regular polygon base how do you identify its height and its slant height?

Its vertical height is that of the perpendicular from the centre
of the base to the apex; the slant height is the length of the
sloping "corner" between two faces.
The height of a regular pyramid is the vertical distance from
the center of base to the top and is usually shown with a line
perpendicular to the base, denoted with a right angle to the
base.
The slant height it the height of the lateral face (the
triangles) from the edge of the base to the top of the pyramid. It
is the height of the triangle, not the pyramid itself.
The slant height will also be the hypotenuse of a right angle
formed from the altitude of the pyramid and the distance from the
center of the base to the edge.

###### Asked in Math and Arithmetic, Algebra, Geometry

### The slant height of a pyramid is 46 ft The base is a square with a side length of 24 ft What is the height of the pyramid Round your answer to the nearest tenth?

If there is a picture, it would be very useful, because the
height and slant height are two sides of a right triangle.
A good picture would show that the bottom side of this triangle
is half the side length of the square. This is a leg of the right
triangle: A=12'
The hypotenuse of the triangle is the slant height: C=46'
The "unknown" height is the other leg of the right triangle:
B=?
The pythagorean theorem A2+B2=C2 gives 144sqft+B2=2116sqft
Solving for B gives B=44.4'
Therefore, the height of the pyramid is 44.4 feet.

###### Asked in Math and Arithmetic, Algebra, Geometry

### What is the slant height of a pyramid that has all sides as equilateral triangles with sides of length of 9 cm and the surface area of the pyramid is 140.4 square cm?

The surface area of the pyramid is superfluous to calculating
the slant height as the slant height is the height of the
triangular side of the pyramid which can be worked out using
Pythagoras on the side lengths of the equilateral triangle:
side² = height² + (½side)²
→ height² = side² - ¼side²
→ height² = (1 - ¼)side²
→ height² = ¾side²
→ height = (√3)/2 side
→ slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm.
----------------------------
However, the surface area can be used as a check:
140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4
So the pyramid comprises 4 equilateral triangles - one for the
base and 3 for the sides; it is a tetrahedron.

###### Asked in Science, Mathematical Finance, Algebra

### How do you find the surface area of a rectangular pyramid?

For a rectangular pyramid (which is not a square bottom) you can
not use the standard formula of Surface Area = B + 1/2 * P * s,
because there is more than one slant height.
A rectangular pyramid is made up of 1 rectangular base
and 4 triangles going up from the base to the top of the
pyramid. The surface area is the area of all five parts added
together
The first bit is a rectangle so you can find the area of it by
multiplying its length times its width.
Now we have four triangles, two of them will have a base which
is the length of the pyramid and two will have a base which is the
width of the pyramid.
The area of a triangle is (1/2*bh), where b is the base (either
length of width of the rectangle) and h is the slant height
(distance from the base to the top of the pyramid).
The triangles with base = length and the triangles with base =
height will have different slant heights. There will be two
triangles of each type so the area of all four triangles will be
2(1/2*ls1) + 2(1/2*ws2) = l*s1 + w*s2
If you have been given both slant heights you have enough
information to answer the question at this stage,
You will have SA = l*w + l*s1 + w*s2
(where l is length, w is width, s1 is the slant length of the
triangles with base l, s2 is the slant length of the triangles with
base w)
If you do not have the slant lengths you will have to use the
Pythagorean Theorem to find them, this will tell you the slant
length of the triangle with base l, will be the square root of
(w/2)2 + h2 where h is the height of the pyramid (distance from
bottom to top through middle of pyramid) similarly the slant length
of the triangle with base w will be the square root of (l/2)2 +
h2