3a+b
It is the same as: 3*(a+b) or simply 3(a+b)
3(a + b) + a = 3a + 3b + a = 4a + 3b
3*(a + b) or 3a + 3b
The algebraic expression is 3(b+5).
1.Start 2. Input a,b,c 3. Sum = a+b+c 4. Average = sum/3 5. Output - Sum,Average 6. Stop
a^3 + b^3 = (a + b)(a^2 - ab + b^2) a^3 - b^3 = (a - b)(a^2 + ab + b^2)
3(a+b)+a
3(b5)
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
No, a polynomial is the sum of any two monomials, i.e., any two terms, for example, a + b, a - b, a2 + b2, x2y -3, etc. ("Sum" may include negative terms.)No, a polynomial is the sum of any two monomials, i.e., any two terms, for example, a + b, a - b, a2 + b2, x2y -3, etc. ("Sum" may include negative terms.)No, a polynomial is the sum of any two monomials, i.e., any two terms, for example, a + b, a - b, a2 + b2, x2y -3, etc. ("Sum" may include negative terms.)No, a polynomial is the sum of any two monomials, i.e., any two terms, for example, a + b, a - b, a2 + b2, x2y -3, etc. ("Sum" may include negative terms.)
If the question is, "What two numbers sum to 37 and have a difference of 3?" Then the answer is 20 and 17 To solve the problem, call the two numbers a and b. Then a + b = 37 therefore b = 37 - a. And a - b = 3 : substitute the value (shown above) for b in this equation. a - (37 - a) = 3 : 2a - 37 = 3 : 2a = 3 + 37 = 40 : a = 20 As a + b = 37 then 20 + b = 37 : b = 37 - 20 = 17