This is impossible. you Must first place the I in front of the 4.
One possibility is : 2 Thieves Crucified with Jesus.
J. B. Tyldesley has written: 'The solution of atmospheric diffusion equations by electrical analogue methods'
//to multiply two matrices... #include<stdio.h> main() { int a[4][4]; int b[4][4]; int c[4][4]; int i,j,k; printf("\n Enter elements into the first matix....\n"); for(i=0;i<4;i++) { for(j=0;j>4;j++) { scanf("%d",&a[i][j]); } } printf("\n Enter elements into the second matrix.....\n"); for(i=0;i<4;i++) { for(j=0;j<4;j++) { scanf("%d",&b[i][j]); } } printf("\n 1st Matrix.....\n"); for(i=0;i<4;i++) { for(j=0;j<4;j++) { printf("\t%d",a[i][j]); } printf("\n"); } printf("\n 2nd Matrix......\n); for(i=0;i<4;i++) { for(j=0;j<4;j++) { printf("\t%d",b[i][j]); } printf("\n"); } for(i=0;i<4;i++) { for(j=0;j<4;j++) { for(k=0;k<4;k++) { c[i][j]+=(a[i][k]*b[k][j]); } } } printf("\n Resultant Matrix...\n"); for(i=0;i<4;i++) { for(j=0;j<4;j++) { printf("\t%d",c[i][j]); } printf("\n"); } }
void main() { int arr[4][4]; int i,j,a,b,f; printf("\nInput numbers to 4*4 matrix"); for(i=0;i<4;i++) { for(j=0;j<4;j++) { printf("\nKey in the [%d][%d]) value",i+1,j+1); scanf("%d",&arr[i][j]); } } for(i=0;i<4;i++) { for(j=0,f=0;j<4;j++) { if(i!=j&&f==0) continue; a=arr[i][j]; b=arr[j][i]; arr[i][j]=b; arr[j][i]=a; f=1; } } for(i=0;i<4;i++) { for(j=0;j<4;j++) printf("%d ",arr[j][i]); printf("\n"); } }
#include<stdio.h> #include<conio.h> main() { int a[4][4],b[4][4],c[4][4],i,j; printf("enter the elements of matrix a"); for(i=0;i<=3;i++) for(j=0;j<=3;j++) scanf("%d",&a[i][j]); printf("the first matris is"); for(i=0;i<=3;i++) { printf("\n"); for(j=0;j<=3;j++) printf("%d",a[i][j]); } printf("Enter the elements of second matrix"); for(i=0;i<=3;i++) for(j=0;j<=3;j++) scanf("%d",&b[i][j]); printf("the second matrix is"); for(i=0;i<=3;i++) { printf("\n"); for(j=0;j<=3;j++) printf("%d",b[i][j]); } for(i=0;i<=4;i++) for(j=0;j<=4;j++) c[i][j]=a[i][j] + b[i][j]; printf("the addition of matrix is"); for(i=0;i<=3;i++) { for(j=0;j<=3;j++) printf("%d\t",c[i][j]); printf("\n"); } getch(); }
Matrix-Addition(a,b)1 for i =1 to rows [a]2 for j =1 to columns[a]3 Input a[i,j];4 Input b[i,j];5 C[i, j] = A[i, j] + B[i, j];6 Display C[i,j];
Type your answer here... 8 miracles of Jesus
4 bottles of champagne in a jeroboam
The answer to this Ditloid is somewhat ridiculous, and very hard indeed. The 6 Heroines of Jane Austin Novels. The answer to this Ditloid is somewhat ridiculous, and very hard indeed. The 6 Heroines of Jane Austin Novels.
J. W. B Money has written: 'Java, or, How to manage a colony, showing a practical solution of the questions now affecting British India'
B. J. Surhoff was born August 4, 1964, in Bronx, NY, USA.
(1) M+B=2*J (2) M=8+B (3) J+B=20 Three equations. Three unknowns. Rewrite (1) M=2*J-B Sub into (2) 2*J-B=8+B Solve for B 2B+8=2J or B+4=J Sub J into (3) 2B + 4 = 20 B = 8 J = 12 M=16