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Answered 2011-02-23 00:38:33

I'm not sure if you mean e^x + 17 or e^(x+17) so we'll do both.

First, the integral of e^x + 17

because these terms are being added you can integrate them separately:

integral((e^x)dx) + integral(17dx)

integral of e^x is just e^x + C

Integral of 17 is 17x + C, so we get:

e^x + 17x + C

Second, the integral of e^(x+17)

we know how to integrate the form e^u, so just do a u substitution



so we get

integral((e^u)du)=e^u + C

resubstitute for u and get e^(x+17) + C

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