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a mountain forms
a plate boundary there are constructive plate boundaries, destructive plate boundaries, conservative plate boundaries and collision plate boundaries
The Are Seven Primary Plates, so there cannot be only Five Boundaries, I know the tectonic Plates are The 1. African Plate 2. Antarctic Plate 3. Eurasian Plate 4. Indo-Australian Plate 5. North American Plate 6. Pacific Plate 7. South American Plate There Are Three Basic types of boundary; Divergent, Convergent and Transform boundaries Hopefull somebody can tell you all their names of the boundaires between them because these different Plates will me touching two or More Plates hence a lot of different boundaries
Area of the square = 10x10=100 in^2 Area of Circle=pi/4*10^2 ~=78.539817 in^2 Area between them is the area of the square minus the area of the circle: 100-78.539817 ~=21.46 in^2
continetal and oceanic
The numbers 2, 3, 5, 7 and 11 are prime (including the boundaries).
The three requirements are that it is a plane (2-dimensional) shape.It is an enclosed area. Its boundaries comprise straight lines.
Mistresses - 2013 Boundaries 2-2 was released on: USA: June 2014
no
a valley
In relation to the area of a circle: pi*radius^2
divergent boundaries happen when 2 plates move apart or divide
Area = (pi/4) x (Diameter)2 Diameter = 2 x sqrt(Area/pi)
The numbers 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29 are prime (including the boundaries).
dry land
Annulus
In Calculus, integration is the process of finding the area under the curve of a function, usually between two boundaries. For example, the area under the curve of the graph y=x between 0 and 1 (the two boundaries) is equal to the area of the triangle formed by the x axis, the graph and a vertical line at x=1. Since this triangle covers half the area of a square of length 1 unit, the integral of y=x from 0 to 1 is 1/2. For more complex curves such as y=x^2, integration is easier and more accurate by finding the anti-derivative, or integral, of y=x^2. Finding the anti-derivative, as the name suggests, is the reverse process of finding a function's derivative. So, the anti-derivative of x^2 is the function whose derivative is x^2. I'm assuming you are familiar with differentiation (the process of finding a derivative of a function) if you are doing problems with integration. So, the anti-derivative of x^2 is (1/3)x^3. The purpose of finding the anti-derivative is to use the Fundamental Theorem of Calculus, which states that the area under the curve of a function from a to b (the two boundaries) is equal to the difference between the values of the function's anti-derivative at b and a. So, plugging in 0 and 1 again for x gives: Area under curve of x^2 from 0 to 1 = (1/3)(1)^3 - (1/3)(0)^3 = (1/3) - 0 = 1/3 Notice the reverse order of the boundaries, since subtraction is not commutative (order matters).