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What is boron the element's atomic weight?
The atomic weight of boron is approximately 10.81 atomic mass units.
What is the equivalent weight of boron?
Boron is a chemical with a symbol of B and an atomic number of 5. The equivalent weight of boron is dependent on the chemical that it is combining with.
What is the atomic weight of bromine?
The atomic mass of Boron (B) is 11 but to be more accurate, the atomic mass is 10.81.
What is the lightest weight metalliod in the periodic table?
Aluminum(26.982) because boron(10.81) is a metalloid.
What is the scientific name for boron?
Boron. That's it. Atomic number: 5. Atomic weight: 10.811. Physical description: Black Semi Metallic.
What is boron the element's atomic weight?
The atomic weight of boron is approximately 10.81 atomic mass units.
What is boron's atomic weight?
10.811
What is the equivalent weight of boron?
Boron is a chemical with a symbol of B and an atomic number of 5. The equivalent weight of boron is dependent on the chemical that it is combining with.
What is the atomic weight of bromine?
The atomic mass of Boron (B) is 11 but to be more accurate, the atomic mass is 10.81.
What is the lightest weight metalliod in the periodic table?
Aluminum(26.982) because boron(10.81) is a metalloid.
What is the atomic weight of a boron atom?
10.811 g/mol
What is the scientific name for boron?
Boron. That's it. Atomic number: 5. Atomic weight: 10.811. Physical description: Black Semi Metallic.
How much did boron weigh?
Boron's atomic weight is 10.81 grams per mole.
What atom contains 5 protons?
Boron, Symbol= B Atomic Weight= 10.811
What are the atomic numbers of boron?
The atomic number of boron is 5.
What is the atomic symbol for boron?
The Atomic Symbol is B
How do you calculate a weighted average such as the atomic mass of boron?
Usually, the weight of an atom would be about twice that of the atomic number. For example, Boron's atomic number is 5, and it has an atomic mass 0f 10.81 amu. This is because of the fact that a neutron and a proton both weight about 1 amu, and an electron is insignificant. To calculate the atomic weight to a higher accuracy than a mere estimate, is beyond me. I hope this helped.
