The balanced molecular equation for the reaction between sodium acetate (NaC2H3O2) and silver nitrate (AgNO3) is:
2NaC2H3O2 + AgNO3 -> 2AgC2H3O2 + NaNO3
The molecular formula for sodium acetate is CH3COONa and for silver nitrate it is AgNO3.
The requested equation is Cu + AgNO3 -> CuNO3 + Ag or Cu + 2 AgNO3 -> Cu(NO3)2 + 2 Ag, depending on whether copper forms its (II) or (I) cations.
The net ionic equation for the reaction between sodium acetate (NaCH3COO) and silver nitrate (AgNO3) is: CH3COO- + Ag+ -> AgCH3COO. This simplified equation highlights the formation of a precipitate of silver acetate (AgCH3COO) when silver ions (Ag+) react with acetate ions (CH3COO-).
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
The balanced equation for sodium bromide (NaBr) and silver nitrate (AgNO3) is: 2NaBr + AgNO3 → 2NaNO3 + AgBr.
The molecular formula for sodium acetate is CH3COONa and for silver nitrate it is AgNO3.
The requested equation is Cu + AgNO3 -> CuNO3 + Ag or Cu + 2 AgNO3 -> Cu(NO3)2 + 2 Ag, depending on whether copper forms its (II) or (I) cations.
The net ionic equation for the reaction between sodium acetate (NaCH3COO) and silver nitrate (AgNO3) is: CH3COO- + Ag+ -> AgCH3COO. This simplified equation highlights the formation of a precipitate of silver acetate (AgCH3COO) when silver ions (Ag+) react with acetate ions (CH3COO-).
The reaction is:2 AgNO3 + CaCl2 = 2 AgCl(s) + Ca(NO3)2
The net ionic equation for sodium acetate (NaCH3COO) and potassium nitrate (KNO3) is: CH3COO^- + K^+ -> KCH3COO
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
The balanced equation for sodium bromide (NaBr) and silver nitrate (AgNO3) is: 2NaBr + AgNO3 → 2NaNO3 + AgBr.
One balanced equation for the reaction between elemental copper and silver nitrate is Cu + AgNO3 -> CuNO3 + Ag.
The balanced equation for the reaction between silver nitrate (AgNO3) and copper nitrate (Cu(NO3)2) is: 2AgNO3 + Cu -> Cu(NO3)2 + 2Ag
The chemical equation for the reaction between lithium nitrate and lead(II) acetate is: 2LiNO3 + Pb(C2H3O2)2 → 2LiC2H3O2 + Pb(NO3)2. This reaction involves a double displacement reaction where lithium and lead ions swap partners with the nitrate and acetate ions.
This equation is: 2 AgNO3 + K2CrO4 => Ag2CrO4 + 2 KNO3.
Zn(NO3)2 + Na3PO4 yields Zn3(PO4)2 + NaNO3 with zinc phosphate being the precipitate.