Formula: LiAlI4
It is aprecipitate chemical reaction.The chemical equation of aluminum iodide and leadII acetate is given as follows.. 2AlI3(aq) + 3Pb(C2H3O2)2(aq) --> 3PbI2(s) + 2Al(C2H3O2)3(aq).The above is a balanced equation.
Lithium iodide is a chemical compound, not a mixture.
Solid lithium iodide decomposes into solid lithium and iodine gas.
The chemical reaction isȘAlI3 + 3 Br2 = 2 AlBr3 + 3 I2
Yes. Aluminum will replace the iron in the iron iodide in a single replacement reaction. The chemical equation is Al(s) + FeI2(aq) --> Fe(s) + AlI3(aq).
It is aprecipitate chemical reaction.The chemical equation of aluminum iodide and leadII acetate is given as follows.. 2AlI3(aq) + 3Pb(C2H3O2)2(aq) --> 3PbI2(s) + 2Al(C2H3O2)3(aq).The above is a balanced equation.
Lithium iodide is a chemical compound, not a mixture.
LiIAdded:LiI is the formula of lithium iodide, often misspelled as '...iodine'
Solid lithium iodide decomposes into solid lithium and iodine gas.
Lithium carbonate + Iron(II) iodide ----> Lithium iodide + Iron(II) carbonateLi2CO3 + FeI2 ----> 2 LiI + FeCO3
The chemical reaction isȘAlI3 + 3 Br2 = 2 AlBr3 + 3 I2
Yes. Aluminum will replace the iron in the iron iodide in a single replacement reaction. The chemical equation is Al(s) + FeI2(aq) --> Fe(s) + AlI3(aq).
The chemical reaction is the following: 2 Al + 3 I2--------2 AlI3
Aluluminium iodide is AlI3.
AI Aluminum iodide: The chemical formula is AlI3 In solution 4 ions: Al3+ an 3 I- (iodide)
AlI3
Chlorine does react with lithium iodide to produce free iodine and lithium chloride according to the equation Cl2 + 2 LiI -> 2 LiCl +I2.