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It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.

It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.

It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.

It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.

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11y ago

It depends on the combination. Real numbers are closed with respect to arithmetical operations (+, -, *, /), as well as integer powers (exponents). So a combination of real numbers using any of these operators will yield a real number. But the set is not closed with respect to some fractional powers - for example, the square root of a negative number is not real.

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Q: What is the combination of real numbers in math?
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