This compound id BBr3 - boron tribromide.
The simplest formula for the compound formed between boron and fluorine would be BF3, which is boron trifluoride. Boron typically forms compounds by sharing 3 electrons with each fluorine atom, resulting in a molecule with a boron atom at the center and three fluorine atoms surrounding it.
No, bromine and carbon would not form an ionic compound. Carbon typically forms covalent bonds and bromine can also form both covalent and ionic bonds, depending on the element it is reacting with. In this case, a covalent bond would be more likely between bromine and carbon.
The compound made of magnesium (Mg) and bromine (Br) would most likely have the formula MgBr2, where magnesium has a +2 charge and bromine has a -1 charge, resulting in a 1:2 ratio of magnesium to bromine atoms.
Yes and No, because Barium has two valence electrons and Bromine has 7, which would add up to 9 valence electrons when you can only have 8 if you want to be positively charged, so naturally they would not bond with each other. If they did end up bonding somehow, they would be negatively charged with 1 valence electron and only then could that be bonded with another Bromine atom.
False: A compound whose molecules contain one boron atom and three fluorine atoms would be named "monoboron trifluoride" or simply "boron trifluoride".
The simplest formula for the compound formed between boron and fluorine would be BF3, which is boron trifluoride. Boron typically forms compounds by sharing 3 electrons with each fluorine atom, resulting in a molecule with a boron atom at the center and three fluorine atoms surrounding it.
No, bromine and carbon would not form an ionic compound. Carbon typically forms covalent bonds and bromine can also form both covalent and ionic bonds, depending on the element it is reacting with. In this case, a covalent bond would be more likely between bromine and carbon.
An ionic bond. A typical metal - non-metal compound. Magnesium (Mg) reacts with Bromine (Br2) to form Magnesium Bromide (MgBr2) which has an ionic formula of Mg2+ (Br-)2.
The compound made of magnesium (Mg) and bromine (Br) would most likely have the formula MgBr2, where magnesium has a +2 charge and bromine has a -1 charge, resulting in a 1:2 ratio of magnesium to bromine atoms.
Yes and No, because Barium has two valence electrons and Bromine has 7, which would add up to 9 valence electrons when you can only have 8 if you want to be positively charged, so naturally they would not bond with each other. If they did end up bonding somehow, they would be negatively charged with 1 valence electron and only then could that be bonded with another Bromine atom.
False: A compound whose molecules contain one boron atom and three fluorine atoms would be named "monoboron trifluoride" or simply "boron trifluoride".
The formula for the compound formed between lithium ion (Li+) and bromine ion (Br-) is LiBr. Lithium being a group 1 element with a +1 charge and bromine being a group 17 element with a -1 charge, they combine in a 1:1 ratio to form a stable ionic compound.
hemiheptoxyde de fluor in french xD you only have to translate it
In the chemical formula, the cation (potassium) would be written first followed by the anion (bromine). Therefore, the compound would be named potassium bromide.
When bromine water is added to an unsaturated organic compound, the solution will turn from orange to colorless as the bromine reacts with the double bonds in the compound. This reaction is a test for unsaturation in organic molecules, as saturated compounds do not react with bromine water in the same way.
That would be Bromine, the only halogen element that is liquid at SATP. It's number 35 on the Periodic Table of the Elements and is commonly found in ionic compounds with metals from groups I or II.
The reaction of iron(II) salts with bromine is a redox reaction forming iron(III). The aqueous reaction with bromine water is typical:- 2Fe2+ + Br2 -> 2Fe3+ + 2Br- If you started with iron(II) bromide, iron(III) bromide would be formed