The conjugate acid of H2PO4- is H3PO4, which gains a proton in the process.
The conjugate base of NH4+ is NH3 (ammonia). A conjugate base is formed by the removal of a proton (H+) from the parent acid or cation.
The conjugate base of H2AsO4- is HAsO42-. It is formed by removing one proton (H+) from the acid H2AsO4-.
The conjugate base of HPO2-4 is PO3-4. This is obtained by removing a proton (H+) from the acid (HPO2-4) to form its corresponding base (PO3-4).
The conjugate base of SO2-4 is HSO3-.
The conjugate base of H3BO3 is B(OH)4-.
The conjugate base of NH4+ is NH3 (ammonia). A conjugate base is formed by the removal of a proton (H+) from the parent acid or cation.
During an equilibrium in the following reaction.NH(3) + H(2)O NH(4)(+) + OH(-)NH(4) has the ability to give an H+ ion to OH ion and hence is the conjugate acid.
The conjugate base of H2AsO4- is HAsO42-. It is formed by removing one proton (H+) from the acid H2AsO4-.
The conjugate base of HPO2-4 is PO3-4. This is obtained by removing a proton (H+) from the acid (HPO2-4) to form its corresponding base (PO3-4).
The conjugate base of SO2-4 is HSO3-.
To get the complex conjugate, change the sign in front of the imaginary part. Thus, the complex conjugate of -4 + 5i is -4 - 5i.
The conjugate base of H3BO3 is B(OH)4-.
The conjugate base for HSO4- is SO4^2-.
The balanced chemical equation between copper and sulfuric acid is Cu + H2SO4 -> CuSO4 + H2. Since the reaction involves 1 mole of copper reacting with 1 mole of sulfuric acid, if 4 moles of sulfuric acid are reacting, then 4 moles of copper will also react in order to maintain the stoichiometry of the reaction equation.
PO43- (phosphate) is the conjugate base of HPO42- (monohydrogen phosphate)
Since Kw = Ka * Kb, we can rearrange the equation as Kb = Kw / Ka. Plugging in the values, Kb = (1.0 x 10^-14) / (2.5 x 10^-4) = 4.0 x 10^-11. This is the Kb for the conjugate base of the given acid.
Acetic acid's formula is CH3COOH, so it contains 4 hydrogen atoms, two carbon and two oxygen atoms.4 H2 C2 O