For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.
For this one, conjugate of [-3 - 9i] is: -3 + 9i
PO43-
'Conjugate' means ONE proton more (acid) or less (base) than the described acid or base respectively:So the conjugate acid of PO43- (phosphate) is HPO42- (monohydrogen phosphate)
H3PO4 (aq) + H2O (l) ---> 2H3O+ (aq) + PO4-3 (aq)donor acid + acceptor base ---> conjugate acid + conjugate basethe answer above is wrongto form a conjugate, the ion H2PO4 - must lose a hydrogen ion H+i.eH2PO4 - -H+ = HPO4 2-(conjugate base)
The conjugate acid of ClO- is HClO. The conjugate acid of HClO is ClO2. The conjugate acid of HCI is H2Cl. The conjugate acid of Cl- is HCl. The conjugate acid of ClO is HClO2.
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.For this one, conjugate of [-3 - 9i] is: -3 + 9i
PO43-
0 + 5i Its complex conjugate is 0 - 5i
'Conjugate' means ONE proton more (acid) or less (base) than the described acid or base respectively:So the conjugate acid of PO43- (phosphate) is HPO42- (monohydrogen phosphate)
3-2j.
No
phosphate
It is 3 minus 2i
H3PO4 (aq) + H2O (l) ---> 2H3O+ (aq) + PO4-3 (aq)donor acid + acceptor base ---> conjugate acid + conjugate basethe answer above is wrongto form a conjugate, the ion H2PO4 - must lose a hydrogen ion H+i.eH2PO4 - -H+ = HPO4 2-(conjugate base)
H3PO4 (aq) + H2O (l) ---> 2H3O+ (aq) + PO4-3 (aq)donor acid + acceptor base ---> conjugate acid + conjugate basethe answer above is wrongto form a conjugate, the ion H2PO4 - must lose a hydrogen ion H+i.eH2PO4 - -H+ = HPO4 2-(conjugate base)
The conjugate base of HPO4^-2 is PO4^-3 because when HPO4^-2 loses a single hydrogen ion in a reaction, it forms PO4^-3.