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What is the conjugate of -8-4i?
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
What is the value of Kb for its conjugate base CN?
The Kb value for the conjugate base CN- (cyanide ion) is 2.5 x 10^-5.
What is the conjugate acid of cio- HCIO HCI CI- CIO?
The conjugate acid of ClO- is HClO. The conjugate acid of HClO is ClO2. The conjugate acid of HCI is H2Cl. The conjugate acid of Cl- is HCl. The conjugate acid of ClO is HClO2.
What is the conjugate base and conjugate acid for HSO4-?
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
What is the conjugate acid of NO2-?
HNO2 conjugate acid = one more hydrogen conjugate base = one less hydrogen
What is the conjugate of 3 plus 4i?
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
What is the conjugate of -8-4i?
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
What is the conjugate of -6 plus 4i?
-6-4i.
Find the conjugate of 8 plus 4i.?
The conjugate of a complex number is obtained by changing the sign of its imaginary part. For the complex number (8 + 4i), the conjugate is (8 - 4i).
What is the conjugate of the complex number 7-4i?
To get the conjugate simply reverse the sign of the complex part. Thus conj of 7-4i is 7+4i
What is the sum of two complex conjugate number?
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
What is conjugate of 4i open bracket -2 -3i close bracket?
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
What is the quotient of these complex nuimbers (4 plus 4i) (5 plus 4i)?
To find the quotient of the complex numbers ( (4 + 4i) ) and ( (5 + 4i) ), you divide the two: [ \frac{4 + 4i}{5 + 4i}. ] To simplify, multiply the numerator and denominator by the conjugate of the denominator: [ \frac{(4 + 4i)(5 - 4i)}{(5 + 4i)(5 - 4i)} = \frac{(20 - 16i + 20i - 16)}{(25 + 16)} = \frac{(4 + 4i)}{41}. ] This results in ( \frac{4}{41} + \frac{4}{41}i ).
The division of two complex numbers arithematic operation requires the use of complex conjugate?
(3+2i)/(5+4i)If you multiply both sides by the conjugate of the denominator (5-4i), you get:(3+2i)(5-4i)/(5+4i)(5-4i)= (23-2i)/(25 + 16 +20i - 20i)= (23-2i)/41The denominator is now real, because the i terms cancelAs a general formula (easy to expand) this would be:(a+bi)/(c+di) = [(ac+bd) + (bc-ad)i] / (c^2 + d^2)It's a very easy method, but if you're the sort of person who loves using general formulas, there it is.
2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is the multiplicative inverse of 3-4i divided by 5 plus 2i?
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
Find the absolute value of the complex number z equals 3 plus 4i?
('|x|' = Absolute value of x) |3+4i| = √(32 + 42) = √(9+16) = √25 = 5 Thus |3+4i| = 5.
