Want this question answered?
The standard form is 7x + 2y - 3 = 0
Subtract by 7x and divide by 2.
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19
7x = -3y + 12
-7x - 2y = -3
The standard form is 7x + 2y - 3 = 0
Subtract by 7x and divide by 2.
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
7x = -3y + 12
Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19
7x-2y = 14 -2y = -7x+14 y = 3.5x-7
2y + 7x + y-1?
3x - 2y + 7x + 4y = 3x + 7x - 2y +4y = (3+7)x + (-2+4)y = 10x + 2y
It is: y = -3.5x+2.5 in slope-intercept form
4x-2y+3x+2y When simplified: 7x
-11/6