On the Earth's surface, the depth is between 8-64 kilometers.
4 million approx, 40 killometres = 40,000 metres x 100 = 4 million centimetres
The density of Earth's mantle varies depending on its depth. The part right below the crust has a density of about 3.4 grams per cubic centimeter while the lowest part of the mantle is 5.6 grams per cubic centimeter.
it is 3.0 g.\cm to the third power. Your welcome.
About 2700 kilometers
4152 kg/m3The earths mantle has a density of about 3.3 g/cubic cm.
A line has no width nor depth, so it has no surface, thus its surface area is 0 cm2
suface area: 378cm2 Volume: 882cm3
4 million approx, 40 killometres = 40,000 metres x 100 = 4 million centimetres
Out in the open ocean, light penetrates only to a depth of a few hundred meters. The deep zone is located below the surface. The deep zone is almost totally dark.
3 cm if you times divide by a number 1 3rd of it depth in cm.
20-30 Cm below the surface of the pool water.
The density of Earth's mantle varies depending on its depth. The part right below the crust has a density of about 3.4 grams per cubic centimeter while the lowest part of the mantle is 5.6 grams per cubic centimeter.
It has volume √187200 cm³ which is approx 432.7 cu cmIt has dimensions: √(276 12/13) cm by √(36 1/9) cm by √(18 18/25) cmwhich is approx: 16.6 cm by 6 cm by 4.3 cm--------------------------------------------------------------------How this is solved:It has the dimensions of a cuboid are length, width and depth.Thus the three adjacent faces are given by:length × width = 100 cm²width × depth = 72 cm²depth × length = 26 cm²Multiplying all three equations together gives:(length × width) × (width × depth) × (depth × length) = 100 cm² × 72 cm² × 26 cm²→ length² × width² × depth² = 187200 cm^6→ (length × width × depth)² = (187200 cm³)²→ length × width × depth = √187200 cm³But for a cuboid:volume = length × width × depth = √187200 cm³ ≈ 432.7 cu cmGoing back to the original three equations above, rearranging (3):3) depth × length = 26 cm²→ depth = 26 cm² ÷ lengthSubstituting in (2):2) width × depth = 72 cm²→ width × (26 cm² ÷ length) = 72 cm²→ width = 72/26 × lengthSubstituting in (1):1) length × width = 100 cm²→ length × (72/26 × length) = 100 cm²→ length² = 2600/72 cm²→ length = √(36 1/9) cm ≈ 6 cmSubstituting in (3):3) depth × length = 26 cm²→ depth × sqrt(36 1/9) cm= 26 cm²→ depth = 26 ÷ sqrt(36 1/9) cm→ depth = √(18 18/25) cm ≈ 4.3 cmSubstituting in (2):2) width × depth = 72 cm²→ width × sqrt(18 18/25) cm = 72 cm²→ width = 72 ÷ sqrt(18 18/25) cm→ width = √(276 12/13) cm ≈ 16.6 cmNote that length, width and depth can be any of the three dimensions; the cuboid has dimensions:√(276 12/13) cm by √(36 1/9) cm by √(18 18/25) cmwhich is approximately:16.6 cm by 6 cm by 4.3 cm
20 cm
They are surface fish so the depth of the water is immaterial to them.
The fishing liine will rise with the tide, therefore it will rremain 15.5227 ft below the surface
32 cm3