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Let f be differentiable on [a,b] and suppose that k is a number between f'(a) and f'(b). Then there exists a point c ε (a,b) such that f'(c)=k.
If the function is continuous in the interval [a,b] where f(a)*f(b) < 0 (f(x) changes sign ) , then there must be a point c in the interval a<c<b such that f(c) = 0 . In other words , continuous function f in the interval [a,b] receives all all values between f(a) and f(b)
∫ f(x)/[(f(x) + b)(f(x) + c)] dx = [b/(b - c)] ∫ 1/(f(x) + b) dx - [c/(b - c)] ∫ 1/(f(x) + c) dx b ≠c
Using calculus to see if the function f(x) is continuous at a point (point c) involves three steps. These three conditions must be met: 1. f(c) exists, is defined 2. lim f(x) exists x-->c 3. f(c)= lim f(x) x-->c
185°F is equal to 85°C. To convert F° to C°, subtract 32 and multiply by .5556 (or 5/9).185 - 32 = 153 x .5556 = 85.0068 or 85° rounded down.
5 F = -15 C 5 C = 41 F The difference is 20 C or 36 F.
The Difference b/w FOB and C&F is FOB + Insurance + Freight = C&F I.e Insurance and freight in both the valuation.
Polar covalent. There is a significant difference in electronegativity between C and F.
We got the formula: speed of medium c = frequency f times wavelength lambda.lambda = c / f has a length unit.Frequency f is 1/time = c / lambda.That shows the difference between the wavelength lambda and the frequency f.
Franchisee is the middle man between principle and retail customer C and F agent is the middleman between principle and wholesailer
Polar covalent. There is a significant difference in electronegativity between C and F.
25
(C - F) percent.
12 deg F is -11.11... deg C so the difference is 5.11... degrees in the Celsius scale. However, since neither scale is absolute it would be incorrect to say that the difference is 5.11... deg C. It would be correct to say that the difference is 5.11... Kelvin since that is an absolute scale. All that sounds rather complicated and an illustration might help. To start with we know (or can calculate) that -40 deg C = -40 deg F. So what is the difference between -40 deg C and -40 deg F? Since -40 deg F = -40 deg C, the difference is 0 deg on the Celsius scale. But 0 deg C is 32 deg F so does that make the difference 32 deg F? No, because the difference on the F scale is also 0 deg.
32 f 0 c
In principle, this is a simple subtraction problem. 30 °F - -13 °F = 43 °F This is equivalent to a difference of 23.89 °C.
Yes, it does as there is a considerable electronegativity difference between given atoms.