the maker.
@ .05 inches
the 40 cal is a little bigger then the 357
9mm = .355 40 cal = .40
Yes
The caliber for one.
There are various difference, but the most common answer would be the .45 is .05 of an inch larger in diameter than a .40.
Short answer, a 9mm is smaller in diameter and lighter.
The .40 caliber bullet is a little larger in diameter and is a little heavier (under most circumstances). The .40 will usually have more powder, velocity, and muzzle energy. Also, the .40 is designed for use in a semi-automatic and the .38 is a revolver cartridge.
Size and relative power. A .40 caliber bullet is .40 of an inch and the entire cartridge is 28.8 millimeters long. A .50 caliber (handgun) bullet is .50 of an inch and the entire cartridge is 40.99 millimeters long. The .50 caliber has more powder, more velocity, and more muzzle energy.
.40 Smith & Wesson is a 10x22mm cartridge, whereas the .45 ACP would measure 11.65x23 in metric measurements. The .45 is a larger round, and also a much slower round.
40 cal ACP (not CAP) is the same as 40 cal. S&W. ACP refers to 'automatice cartridge pistol' wheras S&W refers to Smith and Wesson, who also make the 40 cal. cartridge....
The .40 is a larger diameter round. The projectile has a dimension of .4005, versus the 9mm Parabellum, which has a dimension of .356. Of the two, the .40 is the more powerful cartridge.