Algebra

Numbers

Top Answer

There is no difference, only your outcome. The formula for both is x+2

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030 + 31 + 32 = 93 ( I forgot how to find this algebraically )

56.25% is not an integer and so cannot be expressed as a sum, difference, product or quotient of consecutive integers.

Algebraically, X = integer. X + (X + 1) = 89 2X + 1 = 89 2X = 88 X = 44 ------------so X + 1 which is 44 + 1 = 45 ( 44, 45) --------------are your consecutive integers

Algebraically, with X = integers.X + (X + 1) + (X + 2) = 1923X + 3 = 1923X = 189X = 63============solution set

I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.

The first two consecutive prime numbers that have a difference of 20 are the numbers 887 and 907.

There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .

"Consecutive" integers are integers that have no other integer between them.

Algebraically. X = integers. X + (X + 1) = - 379 2X + 1 = - 379 2X = - 380 X = - 190 X + 1 = - 189 - 190 +(- 189) = - 379 ==============solution set of integers

Algebraically, X = integers. X + (X + 1) = 237 gather all terms on the left 2X + 1 = 237 subtract 1 from each side 2X = 236 divide both sides integers by 2 X = 118 --------------so, X + 1 = 119 ----------------so, The two consecutive integers that = 237 are 118 and 119 -------------------

All consecutive integers have a difference of one.

Algebraically. X = integers.X + (X + 1) = 592X + 1 = 592X = 58X = 29X + 1 = 30(29, 30)=======

The two consecutive integers are 19 and 20.

They are consecutive odd integers: 25 and 27.

There is no set of three consecutive integers for 187.

There is no set of three consecutive integers for 106.

The two consecutive, even integers are 350 and 352.

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

There is no set of six consecutive integers for -4.

Consecutive odd integers would be 5 and 7.

Algebraically. X = integers. X + (X + 2) = - 42 2X + 2 = - 42 2X = - 44 X = - 22 X + 2 = - 20 (- 20, - 22 ) ---------------------solution set

Not possible in consecutive integers, nearest is consecutive even integers: 148 & 152

find the two consecutive odd integers with a sum of 152

The sum of two consecutive integers will always be an odd number.

No, it is not. It is the sum of two consecutive integers: 46 and 47.

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